Remember the vital equations for this:
(freezing point depression) = (Depression Constant) * (molality of solution)
Molality = (moles of solute) / (kg of solvent)
Step 1: Find molar mass of glucose
6 carbon * (12.01 g/mol) + 12 hydrogen * (1.01 g/mol) + 6 oxygen (16.00 g/mol)
= 180.18 g/mol
21.5 g glucose * (1 mole glucose / 180.18 g glucose) = 0.119 moles of glucose
Step 2: Convert grams of solvent to kilograms of solvent
255 g H2O * (1 kg/1000g) = 0.255 kg H2O
Step 3: Find the molality of the solution
molality = (moles solute)/(kg solvent)
molality = (0.119 moles glucose)/(0.255 kg H2O solvent) = 0.468 m (molal)
Step 4: Plug into depression equation
FP-depression = (-1.86°C/m) * (0.468 m) = -0.870 <span>°C</span>
Answer:
For the most part, in mitosis, diploid cells are partitioned into two new diploid cells, while in meiosis, diploid cells are partitioned into four new haploid cells.The daughter cells produced by mitosis are identical, whereas the daughter cells produced by meiosis are different because crossing over has occurred.
Explanation:
Answer: The balanced equation is 
.
Explanation:
A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.
For example, 
Here, number of atoms on reactant side are as follows.
The number of atoms on product side are as follows.
In order to balance this equation, multiply Ca by 5 on reactant side. Multiply V by 2 and CaO by 5 on product side. Therefore, the equation can be rewritten as follows.
Now here, number of atoms on reactant side are as follows.
The number of atoms on product side are as follows.
Since, there are same number of atoms on both reactant and product side. So, the equation is now balanced.
Thus, we can conclude that the balanced equation is .
Hello there.
<span>Find the average acceleration of a northbound subway train that slows from 12 m/s to 9.6 m/s in 0.9 s
</span><span>2.7 m/s2
</span>
The product that you obtain if you evaporate the water from the NaoH layer prior to acidifying the layer is salt of <u> para - tery-butyphenol</u>
<u><em>Explanation</em></u>
- Para-tery-butyphenol can be isolate after extracting it into NaOH solution through carrying out
- heating and then cooling,
- then 3M of HCl is added to acidify.
- Then ice bath is done if needed
- finally the precipitate is filtered.
- Para tery butyphenol can be used for production of alkylphenolic.
