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3 years ago

What characteristics are shared by all alkali metals and alkaline earth metals?

Chemistry

1 answer:

serious [3.7K]3 years ago

8 0

Answer:

All alkali and alkaline earth metals dissolves in water to form alkaline solutions.

Explanation:

The alkali metals are found in group one of the periodic table while the alkaline earth metals are found in group 2. These two groups of elements are quite reactive and they react very well with air and water. All the elements in the two groups react with water to give rise to alkaline solutions; solutions whose pH range from 8 to 14.

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Its d. Speed (v) and frequency(f) both stay the same.

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3 years ago

Which of the following would result in being able to dissolve a greater amount of gas in a solution?

Rudik [331]

Being the get-away driver

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3 years ago

PLSSSSS HELP I DONT GET THIS PROBLEMMMM

Aleks [24]

Answer:

C. 7370 joules.

Explanation:

There is a mistake in the statement. Correct form is described below:

<em>Using the above data table and graph, calculate the total energy in Joules required to raise the temperature of 15 grams of ice at -5.00 °C to water at 35 °C. </em>

The total energy needed to raise the temperature is the combination of latent and sensible heats, all measured in joules, and represented by the following model:

$Q = m\cdot [c_{i} \cdot (T_{2}-T_{1})+L_{f} + c_{w}\cdot (T_{3}-T_{2})]$ (1)

Where:

$m$ - Mass of the sample, in grams.

$c_{i}$ - Specific heat of ice, in joules per gram-degree Celsius.

$c_{w}$ - Specific heat of water, in joules per gram-degree Celsius.

$L_{f}$ - Latent heat of fusion, in joules per gram.

$T_{1}$ - Initial temperature of the sample, in degrees Celsius.

$T_{2}$ - Melting point of water, in degrees Celsius.

$T_{3}$ - Final temperature of water, in degrees Celsius.

$Q$ - Total energy, in joules.

If we know that $m = 15\,g$ , $c_{i} = 2.06\,\frac{J}{g\cdot ^{\circ}C}$ , $c_{w} = 4.184\,\frac{J}{g\cdot ^{\circ}C}$ , $L_{f} = 334.72\,\frac{J}{g}$ , $T_{1} = -5\,^{\circ}C$ , $T_{2} = 0\,^{\circ}C$ and $T_{3} = 35\,^{\circ}C$ , then the final energy to raise the temperature of the sample is:

$Q = (15\,g)\cdot \left[\left(2.06\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (5\,^{\circ}C)+ 334.72\,\frac{J}{g} + \left(4.184\,\frac{J}{g\cdot ^{\circ}C}\right)\cdot (35\,^{\circ}C) \right]$

$Q = 7371.9\,J$

Hence, the correct answer is C.

8 0

2 years ago

Equivalent mass of AL2O3

Maru [420]

Answer:

$Mass = 102g$

Explanation:

Given

Compound: $Al_2O_3$

Required

Determine the equivalent mass

In the above compound, we have: 2 Al and 3 (O)

The atomic mass of Aluminium is:

$Al = 27$

The atomic mass of Oxygen is:

$(O) = 16$

So, the equivalent mass is:

$Mass = 2 * 27 + 3 * 16$

$Mass = 54 + 48$

$Mass = 102g$

5 0

3 years ago

Do I use molar mass when the problem gives me grams? (Yes or No), Right answer gets brainliest.

timurjin [86]

Answer:

yes

Explanation:

yes because the molar mass is an intensive property of the substance, that does not depend on the size of the sample. In the International System of Units (SI), the base unit of molar mass is kg/mol. However, for historical reasons, molar masses are almost always expressed in g/mol.

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3 years ago

Read 2 more answers