I'm going on a limb here, but Carbon is a definite. <span />
Answer:
- <u>two molecules of ammonia are formed by the reaction of one nitrogen and three hydrogen molecules.</u>
Explanation:
The balanced chemical equation provides information on:
- <u>Reactants</u>: those are the compounds that appear of the left side of the equation, each with its chemical formula.
- <u>Products</u>: those are the compounds that appear on the right side of the equation, again, each with its chemical formula.
- <u>Ratio</u>: the coefficients of each compound (the number to the left of the chemical formula) represent the ratio of the number of molecules that react and are formed.
In the given equation you have:
- Equation: N₂ + 3H₂ → 2NH₃
- The coefficients are 1 for nitrogen, 3 for hydrogen, and 2 for ammonia. Hence, 2 molecules of ammonia are formed by the reaction of 1 molecule of nitrogen and 3 molecules of hydrogen.
Answer:
Explanation:
2 moles hydrogen reacts with one mole of oxygen to give 2 moles of water.
a ) rate of consumption of hydrogen ( moles per second) is twice the rate of consumption of oxygen .
b ) rate of formation of water ( moles per second ) is twice the rate of consumption of oxygen
c ) rate of formation of water ( moles per second ) is equal to the rate of consumption of hydrogen.
Answer:
Maryland is a Mid-Atlantic state in the United States that is characterized by abundant waterways and coastlines.
The effects of climate change in Maryland include rising sea levels, summer heat waves, and more frequent and violent thunderstorms.
These changes affect the citizens of Maryland, their livelihoods and also the economy of the state.
Answer: Dissociation constant of the acid is
.
Explanation: Assuming the acid to be monoprotic, the reaction follows:
![HA\rightleftharpoons H^++A^-](https://tex.z-dn.net/?f=HA%5Crightleftharpoons%20H%5E%2B%2BA%5E-)
pH of the solution = 6
and we know that
![pH=-log([H^+])](https://tex.z-dn.net/?f=pH%3D-log%28%5BH%5E%2B%5D%29)
![[H^+]=antilog(-pH)](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dantilog%28-pH%29)
![[H^+]=antilog(-6)=10^{-6}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dantilog%28-6%29%3D10%5E%7B-6%7DM)
As HA ionizes into its ions in 1 : 1 ratio, hence
![[H^+]=[A^-]=10^{-6}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D%5BA%5E-%5D%3D10%5E%7B-6%7DM)
As the reaction proceeds, the concentration of acid decreases as it ionizes into its ions, hence the decreases concentration of acid at equilibrium will be:
![[HA]=[HA]-[H^+]](https://tex.z-dn.net/?f=%5BHA%5D%3D%5BHA%5D-%5BH%5E%2B%5D)
![[HA]=0.1M-10^{-6}M](https://tex.z-dn.net/?f=%5BHA%5D%3D0.1M-10%5E%7B-6%7DM)
![[HA]=0.09999M](https://tex.z-dn.net/?f=%5BHA%5D%3D0.09999M)
Dissociation Constant of acid,
is given as:
![K_a=\frac{[A^-][H^+]}{HA}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BA%5E-%5D%5BH%5E%2B%5D%7D%7BHA%7D)
Putting values of
in the above equation, we get
![K_a=\frac{(10^{-6}M).(10^{-6}M)}{0.09999M}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%2810%5E%7B-6%7DM%29.%2810%5E%7B-6%7DM%29%7D%7B0.09999M%7D)
![K_a=1.0001\times 10^{-11}M](https://tex.z-dn.net/?f=K_a%3D1.0001%5Ctimes%2010%5E%7B-11%7DM)
Rounding it of to one significant figure, we get
![K_a=1.0\times 10^{-11}M\approx 10^{-11}M](https://tex.z-dn.net/?f=K_a%3D1.0%5Ctimes%2010%5E%7B-11%7DM%5Capprox%2010%5E%7B-11%7DM)