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3 years ago

8

circuit in Mike’s home is almost at maximum current. If it is a 120 V circuit with about 1/3 of an amp available to safely use,

which bulb would be the maximum wattage Mike could use?

2 answers:

NikAS [45]3 years ago

3 0

Answer:

40 W

Explanation:

The maximum wattage (power) that Mike can use is given by:

$P=VI$

where

V is the voltage

I is the maximum current

In this problem, we have:

$V=120 V$ is the voltage

$I=\frac{1}{3}A=0.33 A$ is the maximum current available

Therefore, the maximum power that could be used is

$P=VI=(120 V)(0.33 A)=40 W$

Free_Kalibri [48]3 years ago

3 0

Answer:

40 W

Explanation:

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