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Rashid [163]
3 years ago
13

A race car traveling at 10. meters per second accelerates at the rate of 1.5 meters per seconds while traveling a distance of 7,

467m. The final speed of the race car is approximately...?
1)1900m/s
2)150 m/s
3) 910 m/s
4) 44m/s
Physics
2 answers:
Arturiano [62]3 years ago
4 0

The final speed of the car is 2) 150 m/s

Explanation:

Since the motion of the car is a uniformly accelerated motion, we can solve the problem by using the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the car in this problem, we have

u = 10 m/s

a=1.5 m/s^2

s = 7,467 m

Solving for v, we find the final velocity (and speed) of the car:

v=\sqrt{u^2+2as}=\sqrt{10^2+2(1.5)(7,467)}=150 m/s

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

aleksklad [387]3 years ago
4 0

Answer:44m/s

Explanation:

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kap26 [50]

Answer:

Magnitude of the resultant force will be 20N in the direction of F_2.

Explanation:

It's given in the question that two forces have been applied on the object given.

Since force is a vector quantity, therefore, it has magnitude and direction both.

F_1=20N

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Both the forces are in the opposite directions.

Therefore, magnitude of the resultant force of these forces will be,

F_2-F_1=40-20

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And the direction of the resultant force will be towards F_2.

Therefore, magnitude of the resultant force will be 20N in the direction of F_2.

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Practice
stiv31 [10]

Answer:

The answer is Letter B The car travel at a constant veloc

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3 years ago
What is the speed of a beam of electrons when under the simultaneous influence of E = 1.64×104 V/m B = 4.60×10−3 T Both fields a
andrezito [222]

Answer: v = 3.57×10^6 m/s; R = 4.42×10^-3m; T = 7.78×10^-9 s

Explanation:

Magnetic force(B) = 4.60×10^-3 T

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Both forces having equal magnitude ;

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qvB = qE

vB = E

v = (1.64×10^4) ÷ (4.60×10^-3)

v = 3.57×10^6 m/s

2.) Assume no electric field

qvB = ma

Where a = v^2 ÷ r

R = radius

a = acceleration

v = velocity

qvB = m(v^2 ÷ R)

R = (m×v) ÷ (|q|×B)

q=1.6×10^-19C

m = 9.11×10^-31kg

R = (9.11×10^-31 * 3.57×10^6) ÷ (1.6×10^-19 * 4.6×10^-3)

R = 32.5227×10^-25 ÷ 7.36×10^-22

R = 4.42×10^-3m

3.) period(T)

T = (2*pi*R) ÷ v

T = (2* 4.42×10^-3 * 3.142) ÷ (3.57×10^6)

T = (27.775×10^-3) ÷(3.57×10^6)

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6 0
4 years ago
a rocket engine can accelerate a rocket launched from rest vertically up with an acceleration of 22.9 m/s2. however, after 50.0
xxTIMURxx [149]

The acceleration of a rocket engine is given here, and after 50 seconds of flight, the engine fails, and we must determine the altitude of the rocket at the time the engine fails.  Because the rocket starts from rest, the time taken is 50 seconds, the initial velocity is zero, and the acceleration is 22.9 meters per second square. So we use the kinamatics equation s equal to v. I t plus half 8 square. There is no acceleration at the start. 22.9 and t is 50 seconds, so displacement 2.86 times 10 to the power 4 is met. This is the rocket's displacement in 50 seconds, so this is the rocket's altitude when the engine fails.

<h3>What exactly is accelerate?</h3>
  • In mechanics, acceleration is defined as the rate of change of an object's velocity with respect to time. Vector quantities are accelerations. The orientation of an object's acceleration is determined by the orientation of its net force.
  • In his second law of motion, Sir Isaac Newton (1642-1727) defined acceleration as the ratio of a force acting on an object to its mass: a = f/m.
  • Accelerate is a verb that means to speed up. When you press the gas pedal, the car accelerates. If you know someone who works at the consulate, you can speed up the process.
  • Acceleration is the rate at which velocity changes over time, both in terms of speed and direction. A point or object moving in a straight line is accelerated if it accelerates or decelerates.
  • Even if the speed is constant, motion on a circle is accelerated because the direction is constantly changing. Both effects contribute to acceleration in all other types of motion.

Hence, There is no acceleration at the start. 22. This is the rocket's displacement in 50 seconds, so this is the rocket's altitude when the engine fails.

To know more about Accelerate refer to:

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3 0
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Jlenok [28]
The Answer is:

O 3s

Hope you got it right.
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