Answer:
The velocity of the other fragment immediately following the explosion is v .
Explanation:
Given :
Mass of original shell , m .
Velocity of shell , + v .
Now , the particle explodes into two half parts , i.e
.
Since , no eternal force is applied in the particle .
Therefore , its momentum will be conserved .
So , Final momentum = Initial momentum
![mv=\dfrac{mv}{2}+\dfrac{mu}{2}\\\\u=v](https://tex.z-dn.net/?f=mv%3D%5Cdfrac%7Bmv%7D%7B2%7D%2B%5Cdfrac%7Bmu%7D%7B2%7D%5C%5C%5C%5Cu%3Dv)
The velocity of the other fragment immediately following the explosion is v .
Answer:
option C
Explanation:
given,
Force on the object = 10 N
distance of push = 5 m
Work done = ?
we know,
work done is equal to Force into displacement.
W = F . s
W = 10 x 5
W = 50 J
Work done by the object when 10 N force is applied is equal to 50 J
Hence, the correct answer is option C
<span>Energy exists as light, heat, sound, mass, moving objects, gravity, fuel, chemicals, and electricity.</span>
Answer:
Increase the charge of one particle by a factor of 16
Explanation: