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frosja888 [35]
4 years ago
7

How might you explain the difference between the ph values of the 0.01 m hcl (ph = 1.1) and the 0.01 m hc2h3o2 (ph = 3.6)? hcl p

roduces less h+. hcl dissociates more. hc2h3o2 produces both h+ and oh-. hc2h3o2 produces more h+?
Chemistry
1 answer:
vitfil [10]4 years ago
5 0

Answer:

HCl ionizes more

Explanation:

pH is inversely proportional to the concentration of hydronium ions. It may be calculated by the formula pH = -log[H_3O^+].

Hydrochloric acid is one of the six strong acids and it ionizes to hydronium cations and chloride anions to an extent of about 100 %, meaning the molarity of hydronium would be equal to the initial molarity of hydrochloric acid.

Acetic acid is a weak acid which only partially ionizes, while the majority of acid stays in a molecular form. The same molarity of acetic acid would produce a much lower amount of hydronium as a result.

Therefore, pH of a weak acid would be greater than pH of a strong acid considering we start with the same molarity of eah.

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When determining if a bond is polar, we must evaluate the difference in electronegativity (δen) of the atoms involved in the bon
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The electronegativity of an atom is the tendency of an atom in a compound or molecule to attract bonding electrons unto itself. A polar bond is formed when there is an uneven distribution of charges in the molecule brought about by differences in the electronegativities of the atoms in the bonds. These differences create regions of partially positive and partially negative charges. A nonpolar bond only have very small differences in the electronegativity of the bonding atoms. 

Generally, when the difference in electronegativity is less than 0.5, the bond is polar. When the difference is between 0.5 and 1.7, the bond is polar. Finally, when the difference is greater than 1.7, the bond is ionic, which means that the bonding electron is very much attracted to the highly electronegative atom that it is transferred to the said atom instead of merely being shared by the atoms in the bond. 
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3 years ago
alculate the standard enthalpy of formation of ethanoic acid given that the standard enthalpy of combustion for carbon is –394 k
agasfer [191]

Answer:

The standard enthalpy of formation of ethanoic acid is -484 kJ/mol.

Explanation:

C(g)+O_2(g)\rightarrow CO_2(g),\Delta H_{1, comb}=-394 kJ/mol...[1]

H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l),\Delta H_{2, comb}=-286 kJ/mol..[2]

CH_3COOH(l)+2O_2(g)\rightarrow 2CO_2(g)+2H_2O(l),\Delta H_{3, comb}=-876 kJ/mol..[3]

The standard enthalpy of formation of ethanoic acid :

2C(g)+2H_2(g)+O_2(g)\rightarrow CH_3COOH, \Delta H_{4}=?..[4]

Using Hess's law to calculate :

2 × [1] + 2 × [2] - [3] = [4]

\Delta H_4=2\times (-394 kJ/mol)+2\times (-286 kJ/mol) - (-876 kJ/mol)

=\Delta H_4=-484 kJ/mol

The standard enthalpy of formation of ethanoic acid is -484 kJ/mol.

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