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lisov135 [29]
3 years ago
9

Freon−12 (CF2Cl2), widely used as a refrigerant and aerosol propellant, is a dangerous air pollutant. In the troposphere, it tra

ps heat 25 times as effectively as CO2, and in the stratosphere, it participates in the breakdown of ozone. Freon−12 is prepared industrially by reaction of gaseous carbon tetrachloride with hydrogen fluoride. Hydrogen chloride gas also forms. How many grams of carbon tetrachloride are required for the production of 28.5 dm3 of Freon−12 at 21°C and 1.62 atm?
Chemistry
1 answer:
ValentinkaMS [17]3 years ago
8 0

<u>Answer:</u> The mass of carbon tetrachloride required is 293.8 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

PV=nRT

where,

P = pressure of Freon-12 = 1.62 atm

V = Volume of Freon-12 = 28.5dm^3=28.5L     (Conversion factor:  1dm^3=1L )

T = Temperature of Freon-12 = 21^oC=[21+273]K=294K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles Freon-12 = ?

Putting values in above equation, we get:

1.62atm\times 28.5L=n\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 294K\\n=\frac{1.62\times 28.5}{0.0821\times 294}=1.91mol

The chemical equation for the formation of Freon-12 follows:

CCl_4+2HF\rightarrow CF_2Cl_2+2HCl

By Stoichiometry of the reaction:

1 mole of Freon-12 is formed by 1 mole of carbon tetrachloride

So, 1.91 moles of Freon-12 will be formed by = \frac{1}{1}\times 1.91=1.91mol of carbon tetrachloride

To calculate the mass of carbon tetrachloride, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of carbon tetrachloride = 153.82 g/mol

Moles of carbon tetrachloride = 1.91 moles

Putting values in above equation, we get:

1.91mol=\frac{\text{Mass of carbon tetrachloride}}{153.82g/mol}\\\\\text{Mass of carbon tetrachloride}=(1.91mol\times 153.82g/mol)=293.8g

Hence, the mass of carbon tetrachloride required is 293.8 grams.

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Design a test to determine whether thorium-234 also emits particles. First, explain how Rutherford’s experiment measured positiv
liubo4ka [24]

The characteristics of the α and β particles allow to find  the design of an experiment to measure the ²³⁴Th particles is:

  • On a screen, measure the emission as a function of distance and when the value reaches a constant, there is the beta particle emission from ²³⁴Th.
  • The neutrons cannot be detected in this experiment because they have no electrical charge.

In Rutherford's experiment, the positive particles directed to the gold film were measured on a phosphorescent screen that with each arriving particle a luminous point is seen.

The particles in this experiment are α particles that have two positive charge and two no charged is a helium nucleus.

The test that can be carried out is to place a small ours of Thorium in front of a phosphorescent screen and see if it has flashes, with the amount of them we can determine the amount of particle emitted per unit of time.

Thorium has several isotopes, with different rates and types of emission:

  • ²³²Th emits α particles, it is the most abundant 99.9%
  • ²³⁴Th emits β particles, exists in small traces.

In this case they indicate that the material used is ²³⁴Th, which emits β particles that are electrons, the detection of these particles is more difficult since it has one negative charge, it has much lower mass, but they can travel further than the particles α, therefore, for what type of isotope we have, we can start measuring at a small distance and increase the distance until the reading is constant. At this point all the particles that arrive are β, which correspond to ²³⁴Th.

Neutron detection is much more difficult since these particles have no charge and therefore do not interact with electrons and no flashing on the screen is varied.

In conclusion with the characteristics of the α and β particles we can find the design of an experiment to measure the ²³⁴Th particles is:

  • On a screen, measure the emission as a function of distance and when the value reaches a constant, there is the β particle emission from ²³⁴Th.
  • The neutrons cannot be detected in this experiment because they have no electrical charge.

Learn more about radioactive emission here: brainly.com/question/15176980

7 0
2 years ago
What volume of 24% trichloroacetic acid (tca) is needed to prepare eight 3 ounce bottles of 10% tca solution?
Sever21 [200]

Answer:

295.7 mL of 24% trichloroacetic acid (tca) is needed .

Explanation:

Let the volume of 24% trichloroacetic acid solution be x

Volume of required 10% trichloroacetic acid solution =8 bottles of 3 ounces

= 24 ounces = 709.68 mL

(1 ounces =  29.57 mL)

Amount of trichloroacetic acid in 24% solution of x volume of solution will be equal to amount of trichloroacetic acid in 10% solution of volume 709.68 mL.

x\times \frac{24}{100}=709.68 mL\times \frac{10}{100}

x = 295.7 mL

295.7 mL of 24% trichloroacetic acid (tca) is needed .

6 0
3 years ago
The enthalpy of solution (∆H) of KOH is -57.6 kJ/mol. If 3.66 g KOH is dissolved in enough water to make a 150.0 mL solution, wh
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When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

3.66g \times \frac{1mol}{56.11g} \times \frac{(-57.6kJ)}{mol} = -3.76 kJ

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

Qr+Qa = 0\\\\Qa = -Qr = 3.76 kJ

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

150.0 mL \times \frac{1.02g}{mL}  = 153 g

Given the specific heat capacity of the solution (c) is 4.184 J/g・°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

Qa = c \times m \times \Delta T\\\\\Delta T = \frac{Qa}{c \times m} = \frac{3.76 \times 10^{3}J  }{\frac{4.184J}{g.\° C }  \times 153g} = 5.87 \° C

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

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7 0
2 years ago
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mr_godi [17]

Answer:

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6 0
3 years ago
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An aqueous solution of methanol (MM = 32.04 g/mol) has a molality of 8.83 m and a density of 1.15 g/mL. What is the molarity of
hodyreva [135]

We have that the  the molarity of methanol in the solution is mathematically given as

Morality=7.91mol/l

<h3>Chemical Reaction</h3>

Question Parameters:

An <u>aqueous </u><em>solution </em>of methanol (MM = 32.04 g/mol)

A molality of 8.83 m and a density of 1.15 g/mL.

Generally the equation for the   is mathematically given as

Morality=\frac{moles of solute }{mass of the solvent}

where

Mass of solution=(100+282.2)

Mass of solution=1289.9

Volume=1289.9/1.15

Volume=1.115L

Therefore

Morality=\frac{moles of solute }{mass of the solvent}

Morality=8.83/1.115

Morality=7.91mol/l

For more information on Chemical Reactionvisit

brainly.com/question/11231920

7 0
2 years ago
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