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Bond [772]
3 years ago
14

Which is an intensive property of a substance?

Chemistry
2 answers:
Illusion [34]3 years ago
8 0
I am pretty sure it is density
timama [110]3 years ago
6 0

Answer:

Density.

Explanation:

That is density because it does not depend on the amount of the substance.

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10. Which statement about cellular respiration in plants and animals is true?
kogti [31]

Answer:

Ⓑ Both plants and animals release energy from glucose/sugar in cellular respiration.

3 0
3 years ago
Read 2 more answers
Based on the information given about capsules, which of the following types of molecules would you suspect comprises an S. pneum
Sergio039 [100]

"Polysaccharide carbohydrate" comprises an S. pneumoniae capsule.

<u>Option:</u> C

<u>Explanation:</u>

The lengthy sequences of carbohydrate molecules, primarily polymeric carbohydrates constructed of units of monosaccharides linked together through glycosidic connections, understood as Polysaccharides. This carbohydrate can respond to water by catalyzing amylase enzymes, which generate component sugars.

A major human pathogen is Streptococcus pneumoniae or pneumococcus. The virulence is primarily due to its polysaccharide envelope, which protects it from the recipient immune response, and this has led to comprehensive study of the shell.

8 0
3 years ago
(6) Compare a CSTR with a PFR below. a. A flow of 0.3 m3/s enters a CSTR (volume of 200 m3) with an initial concentration of spe
Dmitry [639]

Answer:

Explanation:

Given that:

The flow rate Q = 0.3 m³/s

Volume (V) = 200 m³

Initial concentration C_o = 2.00 ms/l

reaction rate K = 5.09 hr⁻¹

Recall that:

time (t) = \dfrac{V}{Q}

time (t) = \dfrac{200}{0.3}

time (t) = 666.66 \ sec

time (t) = \dfrac{666.66 }{3600} hrs

time (t) = 0.185 hrs

\text{Using First Order Reaction:}

\dfrac{dc}{dt}=kc

where;

t = \dfrac{1}{k} \Big( \dfrac{C_o}{C_e}-1 \Big)

0.185 = \dfrac{1}{5.09} \Big ( \dfrac{200}{C_e}- 1 \Big)

0.942 =  \Big ( \dfrac{200}{C_e}- 1 \Big)

1+ 0.942 =  \Big ( \dfrac{200}{C_e} \Big)

\dfrac{200}{C_e} = 1.942

C_e = \dfrac{200}{1.942}

\mathbf{C_e = 102.98 \ mg/l}

Thus; the concentration of species in the reactant = 102.98 mg/l

b). If the plug flow reactor has the same efficiency as CSTR, Then:

t _{PFR} = \dfrac{1}{k} \Big [ In ( \dfrac{C_o}{C_e}) \Big ]

\dfrac{V_{PFR}}{Q_{PFR}} = \dfrac{1}{k} \Big [ In ( \dfrac{C_o}{C_e}) \Big ]

\dfrac{V_{PFR}}{Q_{PFR}} = \dfrac{1}{5.09} \Big [ In ( \dfrac{200}{102.96}) \Big ]

\dfrac{V_{PFR}}{Q_{PFR}} =0.196 \Big [ In ( 1.942) \Big ]

\dfrac{V_{PFR}}{Q_{PFR}} =0.196(0.663)

\dfrac{V_{PFR}}{0.3 hrs} =0.196(0.663)

\dfrac{V_{PFR}}{0.3*3600 sec} =0.196(0.663)

V_{PFR} =0.196(0.663)*0.3*3600

V_{PFR} = 140.34 \ m^3

The volume of the PFR is ≅ 140 m³

3 0
3 years ago
Really need help now please help!!
Zielflug [23.3K]
I'm sorry but the picture isn't clear enough
7 0
3 years ago
The gas that makes up about 12 percent of the earths atmosphere is ?
ElenaW [278]

Answer:

You may be referring to the gas that makes up 21% of the earth's atmosphere, which is oxygen.

Explanation:

According to NASA, the gases in Earth's atmosphere include:

Nitrogen — 78 percent

Oxygen — 21 percent

Argon — 0.93 percent

Carbon dioxide — 0.04 percent

(Trace amounts of neon, helium, methane, krypton and hydrogen, as well as water vapor)

7 0
4 years ago
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