Answer:
81.04°C
Explanation:
Heat loss by water = Heat gained by Aluminum
Heat loss by water;
H = MCΔT
ΔT = 100 - T2
M = 580g
c = 4.2
H = 580 * 4.2 (100 - T2)
H = 243600 - 2436T2
Heat ganed by Aluminium
H = MCΔT
ΔT = T2 - 24
M = 900g
c = 0.9
H = 900 * 0.9 (T2 - 24)
H = 810 T2 - 19440
243600 - 2436T2 = 810 T2 - 19440
243600 + 19440 = 810 T2 + 2436T2
263040 = 3246 T2
T2 = 81.04°C
Assumption;
Assume that energy diffuses throughout the pan and water so that all parts reach the same final temperature.
Answer:

Explanation:
1. Write the balanced chemical equation.

2. Calculate the moles of HCOOH

3. Calculate the moles of NaOH.

4. Calculate the volume of NaOH

Equilibrium
N₂(g) + 3H₂(g) ⇔ 2NH₃(g)
If the concentration of the reactants is added, the system will reduce the concentration of the reactants by shifting towards the products and vice versa if the concentration of the reactants is decreased the system will shift towards the reactants.
ammonia is removed from the reaction mixture ⇒ it means the ammonia is reduced then the equilibrium shifts to the right