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3 years ago

The gas that makes up about 12 percent of the earths atmosphere is ?

Chemistry

1 answer:

ElenaW [278]3 years ago

7 0

Answer:

You may be referring to the gas that makes up 21% of the earth's atmosphere, which is oxygen.

Explanation:

According to NASA, the gases in Earth's atmosphere include:

Nitrogen — 78 percent

Oxygen — 21 percent

Argon — 0.93 percent

Carbon dioxide — 0.04 percent

(Trace amounts of neon, helium, methane, krypton and hydrogen, as well as water vapor)

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What type of reaction is shown in the following chemical equation in NH3+HC1 NH4C1

natulia [17]

Explanation:

combination reaction

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2 years ago

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The following reaction is a _______ reaction.

jasenka [17]

Compound reaction :)

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3 years ago

580 grams of boiling water (temperature 100°C, specific heat capacity 4.2 J/K/gram) are poured into an aluminum pan whose mass i

fenix001 [56]

Answer:

81.04°C

Explanation:

Heat loss by water = Heat gained by Aluminum

Heat loss by water;

H = MCΔT

ΔT = 100 - T2

M = 580g

c = 4.2

H = 580 * 4.2 (100 - T2)

H = 243600 - 2436T2

Heat ganed by Aluminium

H = MCΔT

ΔT = T2 - 24

M = 900g

c = 0.9

H = 900 * 0.9 (T2 - 24)

H = 810 T2 - 19440

243600 - 2436T2 = 810 T2 - 19440

243600 + 19440 = 810 T2 + 2436T2

263040 = 3246 T2

T2 = 81.04°C

Assumption;

Assume that energy diffuses throughout the pan and water so that all parts reach the same final temperature.

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3 years ago

You are given a solution of HCOOH (formic acid) with an approximate concentration of 0.20 M and you will titrate this with a 0.1

jeka57 [31]

Answer:

$\boxed{\text{36 mL}}$

Explanation:

1. Write the balanced chemical equation.

$\rm HCOOH + NaOH $ \longrightarrow$ HCOONa + H$_{2}$O$

2. Calculate the moles of HCOOH

$\text{Moles of HCOOH} =\text{20.00 mL HCOOH } \times \dfrac{\text{0.20 mmol HCOOHl}}{\text{1 mL HCOOH}} = \text{4.00 mmol HCOOH}$

3. Calculate the moles of NaOH.

$\text{Moles of NaOH = 4.00 mmol HCOOH } \times \dfrac{\text{1 mmol NaOH} }{\text{1 mmol HCOOH}} = \text{4.00 mmol NaOH}$

4. Calculate the volume of NaOH

$c = \text{4.00 mmol NaOH } \times \dfrac{\text{1 mL NaOH }}{\text{0.1105 mmol NaOH }} = \textbf{36 mL NaOH }\\\\\text{The titration will require }\boxed{\textbf{36 mL of NaOH}}$

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2 years ago

state the behaviour of equilibrium , of ammonia is removed from the reaction mixture . Explain your answer

OLEGan [10]

Equilibrium

N₂(g) + 3H₂(g) ⇔ 2NH₃(g)

If the concentration of the reactants is added, the system will reduce the concentration of the reactants by shifting towards the products and vice versa if the concentration of the reactants is decreased the system will shift towards the reactants.

ammonia is removed from the reaction mixture ⇒ it means the ammonia is reduced then the equilibrium shifts to the right

5 0

2 years ago