There will be 7.5 g of Be-11 remaining after 28 s.
If 14 s = 1 half-life, 28 s = 2 half-lives.
After the first half-life, ½ of the Be-11 (15 g) will disappear, and 15 g will remain.
After the second half-life, ½ of the 15 g (7.5 g) will disappear, and 7.5 g will remain.
In symbols,
<em>N</em> = <em>N</em>₀(½)^<em>n</em>
where
<em>n</em> = the number of half-lives
<em>N</em>₀ = the original amount
<em>N</em> = the amount remaining after <em>n</em> half-lives
Answer:
See explanation
Explanation:
It is common knowledge that quite a number of people enjoy singing in the shower. There are reasons for this!
In the shower, there are many surfaces that reflect the sound of your voice as you sing. That makes your voice to sound more powerful and have more volume.
The reverberation of the sound makes the sound of your voice stronger and more intense altogether enriching the music produced as you sing.
Answer:
Explanation:
The reaction of gaseous sulfur dioxide and oxygen to form SO3 (g) is:
2SO₂(g) + O₂(g) ⇄ 2SO₃(g)
Kp is defined as the ratio of pressure of products and pressure of reactants:
I hope it helps!
When Cr dissolves in 1 M H₂Cr₂O₇
Cr(s) ⇄ Cr³⁺ + 3 e⁻
Cr₂O₇²⁻ + 14 H⁺ + 6 e⁻ ⇄ 2 Cr³⁺ + 7 H₂O
by multiplying the first equation by 2 and add the 2 equations;
The balanced redox reaction will be:
2 Cr(s) + Cr₂O₇²⁻(aq) + 14 H⁺(aq) → 4 Cr³⁺(aq) + 7 H₂O(l)
Answer:
2.00 M KOH
Explanation:
Divide moles by volume and make sure your volume is in LITERS, not mL.
0.0400 mol KOH / 0.0200 L = 2.00 M KOH