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const2013 [10]
3 years ago
15

the reaction Br2(l)->Br2(g) has a deltaH=30.91 kJ and a deltaS=.0933 kJ/K. at what temperature does this reaction become spon

taneous? Below this temperature, is the forward reaction or the backward reaction favored?
Chemistry
1 answer:
schepotkina [342]3 years ago
4 0

Answer:

The temperature above which the reaction be spontaneous is 331.3 K.

Below this temperature; the backward reaction is the favored reaction.

Explanation:

  • We have an important relation from the third law of thermodynamics:

<em>ΔG = ΔH - TΔS</em>

<em>ΔG is the free energy change of the reaction,</em>

<em> ΔH is the enthalpy change of the reaction,</em>

<em>ΔS is the entorpy change of the reaction,</em>

  • <em>The reaction is spontaneous when ΔG is negative.</em>
  • and ΔG be negative when the value of (TΔS) is higher than the value of (ΔH).

<em>When ΔG = 0, ΔH = TΔS.</em>

For this reaction, ΔH = 30.91 KJ and ΔS = 0.0933 KJ/K.

  • The temperature above which the reaction be spontaneous is:

T = ΔH / ΔS = (30.91 KJ) / (0.0933 KJ/K) = 331.29 K ≅ 331.3 K.

<em>∴ The temperature above which the reaction be spontaneous is 331.3 K.</em>


<em>Below this temperature; the backward reaction is the favored reaction.</em>

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hope this helps!</span>
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