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2 years ago

The theoretical yield of zinc oxide in a reaction is 486 g. what is the percent

Chemistry

1 answer:

Alex787 [66]2 years ago

7 0

82.09% is the percent yield if 399 g is produced. Hence, option C is correct.

<h3>What is the percent yield?</h3>

Percent yield is the percent ratio of actual yield to the theoretical yield.

Given data:

Actual yield = 399 g

Theoretical yield = 486 g

%Yield = $\frac{Actual \;Yield \;X \;100 }{Theoretical \;Yield}$

%Yield = $\frac{399 gX \;100 }{486 g \;Yield}$

= 82.09%

82.09% is the percent yield if 399 g is produced.

Hence, option C is correct.

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The complete table is shown in figure

a) NH3 is polar as the bonds between N and H are polar. Due to asymmetry in the molecule the molecule is polar

The shape of molecule is trigonal pyramidal while its electronic geometry is tetrahedral.

b) CO2: it is a non polar molecule with polar bonds. The molecule becomes non polar as the dipole moment cancel each other. [Dipole moment is a vector quantity]

The shape is linear.

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An unknown compound contains only carbon, hydrogen, nitrogen, and oxygen. Complete combustion of a 2.77 g sample of the compound

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The molecular formula of the unknown compound is determined as C₉H₁₁NO₂.

<h3>Molecular formula of the compound</h3>

The molecular formula is calculated as follows;

CHNO + O₂ ------------> CO₂ + H₂O

Mass of carbon, C: = (6.64 x 12)/44 = 1.81 g in 2.77 g sample

Mass of hydrogen, H: = (1.67 x 2)/18 = 0.186 g in 2.77 g sample

Mass of Nitrogen, N: = (2.77 x 0.143)/1.69 = 0.234 g

Mass of oxygen, O: = 2.77 g - 1.81 g - 0.186 g - 0.234 g = 0.54 g

<h3>molar ratio of the elements: </h3>

C = 1.81 g = 0.15 mol

H = 0.186 g = 0.186 mol

N = 0.234 g = 0.017 mol

O = 0.54 g = 0.0337 mol

divide through with the smallest number of moles (0.017 mol);

C = 9

H = 11

N = 1

O = 2

Molecular formula = C₉H₁₁NO₂

Check the molar mass of the compound = (9 x 12) + (11 x 1) + (14) + (2 x 16) = 165 g/mol

Thus, the molecular formula of the unknown compound is determined as C₉H₁₁NO₂.

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1 year ago

The energy absorbed or released when a neutral atom gains one electron

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It’s one... electron affinity

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The reaction of an Arrhenius acid with an Arrhenius base produces water and A) a salt B) an ester C) an aldehyde D) a halocarbon

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The reaction of an Arrhenius acid with an Arrhenius base produces water and <span>A) a salt</span>

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A nuclear power plant operates at 40.0% efficiency with a continuous production of 1042 MW of usable power in 1.00 year and cons

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Answer:

3.00 x 10^-11 joules / atom of U-235

Explanation:

We know that the formula for Power = Work done (w)/Time (t)

We need to get the joules from power , since Joules is the SI unit of work.

From the formula P = W/t

W = Power (P) * Time (t)

The SI unit for Time is seconds, hence we change 1 year in seconds

1yr * 365 days/yr * 24hrs/day * 60mins/hr * 60 secs/min = 31536000 secs

It was stated in the question that the plant operates at an efficiency of 40%,

Thus to get the true power we divide the power provided in the question by 0.4 or 40%

= X(0.4) = 1042MW

True Power X = 1042/0.4 = 2605MW

Thus true power = 2605 * 10^6 Watts

Now we have the time in seconds and true power in Watts, we then find the work done.

From our above formula P = W/t

W = P*t = (2605* 10^6) (31536000) =

Finally, we can solve for our energy (work):

P = W / T PT = W = (2880x10^6) (31536000) = 8.22 x 10^16 joules

We then calculate the amount of energy released by only 1 single uranium-235 atom.

= 8.22 x 10^16 joules / 1.07x10^6 g U-235 (235 g / 1 mol)(1 mol/6.0210^23 atoms)

= 3.00 x 10^-11 joules / atom of U-235

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