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3 years ago

Relate the changes in molecular motion of particles as hey change from solid to liquid to gas.

Physics

1 answer:

Drupady [299]3 years ago

3 0

Answer:

as they go from solid to liquis to gas they heat up from thermal energy. that thermal energy then excites the molecules making them move faster causing them to change phases.

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A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle

Sunny_sXe [5.5K]

Answer:

a) 5.09 seconds

b) 107.07 meters

Explanation:

a) As we know

$t_2- t_1 = \sqrt{\frac{2 X}{a} }$

Substituting the given values we get

$t_2 - t_1 = \sqrt{\frac{2 * 52}{4} } \\t_2 - t_1 = 5.09$

It takes 5 .09 s for the motorcycle to accelerate until it catches up with the car

$X_{t`2} = v_i \sqrt{\frac{2X}{a} } + 0.5 a\sqrt{\frac{2X}{a} }\\X_{t`2} = (v_i + 0.5 a) \sqrt{\frac{2X}{a} }\\X_{t`2} = ( 19 + 2) \sqrt{\frac{2* 52}{4} }\\X_{t`2} = 21 * 5.09\\X_{t`2} = 107.07$

4 0

3 years ago

How long would it take an object to reach the ground from the top of a building that is 470 feet tall? Round to the nearest tent

Zinaida [17]

Answer:

It would take the object 5.4 s to reach the ground.

Explanation:

Hi there!

The equation of the height of a free-falling object at any given time, neglecting air resistance, is the following:

h = h0 + v0 · t + 1/2 · g · t²

Where:

h = height of the object at time t.

h0 = initial height.

v0 = initial velocity.

g = acceleration due to gravity (-32.2 ft/s² considering the upward direction as positive).

t = time

Let´s supose that the object is dropped and not thrown so that v0 = 0. Then:

h = h0 + 1/2 · g · t²

We have to find the time at which h = 0:

0 = 470 ft - 1/2 · 32.2 ft/s² · t²

Solving for t:

-470 ft = -16.1 ft/s² · t²

-470 ft / -16.1 ft/s² = t²

t = 5.4 s

3 0

4 years ago

While running, a person dissipates about 0.60 J of mechanical energy per step per kilogram of body mass. If a 68 kg person devel

Tresset [83]

Answer:

Speed = 2.25 m/s

Explanation:

(Assume a running step is 1.5 m long)

Given the following data;

Energy = 0.6J

Power = 61 Watts

Mass = 68 kg

To find how fast the person running;

First of all, we would determine the total mechanical energy being dissipated by the person.

Total energy = 0.6 * 68

Total energy = 40.8 Joules

Next, we find the time;

Energy = power * time

40.8 = 61 * time

Time = 61/40.8

Time = 1.5 seconds

Finally, to find the speed;

Speed = distance/time

Speed = number of steps * time

Speed = 1.5 * 1.5

Speed = 2.25 m/s

4 0

3 years ago

If, instead, the ball is revolved so that its speed is 3.7 m/s, what angle does the cord make with the vertical?

Delicious77 [7]

Complete Question:

A 0.50-kg ball that is tied to the end of a 1.5-m light cord is revolved in a horizontal plane, with the cord making a 30° angle with the vertical.

(a) Determine the ball’s speed. (b) If, instead, the ball is revolved so that its

speed is 3.7 m/s, what angle does the cord make with the vertical?

(Check attached image for the diagram.)

Answer:

(a) The ball’s speed, v = 2.06 m/s

(b) The angle the cord makes with the vertical is 50.40⁰

Explanation:

If the ball is revolved in a horizontal plane, it will form a circular trajectory,

the radius of the circle, R = Lsinθ

where;

L is length of the string

The force acting on the ball is given as;

F = mgtanθ

This above is also equal to centripetal force;

$mgTan \theta = \frac{mv^2}{R} \\\\Recall, R = Lsin \theta\\\\mgTan \theta = \frac{mv^2}{Lsin \theta}\\\\v^2 = glTan \theta sin \theta\\\\v = \sqrt{glTan \theta sin \theta} \\\\v = \sqrt{(9.8)(1.5)(Tan30)(sin30)} \\\\v = 2.06 \ m/s$

(b) when the speed is 3.7 m/s

$v = \sqrt{glTan \theta sin \theta} \ \ \ ;square \ both \ sides\\\\v^2 = glTan \theta sin \theta\\\\v^2 = gl(\frac{sin \theta}{cos \theta}) sin \theta\\\\v^2 = \frac{gl*sin^2 \theta}{cos \theta} \\\\v^2 = \frac{gl*(1- cos^2 \theta)}{cos \theta}\\\\gl*(1- cos^2 \theta) = v^2cos \theta\\\\(9.8*1.5)(1- cos^2 \theta) = (3.7^2)cos \theta\\\\14.7 - 14.7cos^2 \theta = 13.69cos \theta\\\\14.7cos^2 \theta + 13.69cos \theta - 14.7 = 0 \ \ \ ; this \ is \ quadratic \ equation\\\\$

$Cos\theta = \frac{13.69\sqrt{13.69^2 -(-4*14.7*14.7)} }{14.7} \\\\Cos \theta = 0.6374\\\\\theta = Cos^{-1}(0.6374)\\\\\theta = 50.40 ^o$

Therefore, the angle the cord makes with the vertical is 50.40⁰

7 0

3 years ago

2) How many significant figures are in the number 0.0037010?<br>

Nesterboy [21]

Answer:

Explanation:

a significant figure is any number then is more than 0 before a decimal place

8 0

3 years ago