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2 years ago

Which amount of power is the smallest?

Physics

2 answers:

Ede4ka [16]2 years ago

4 0

The correct answer is

D- 4 watts

In fact, the different prefixes correspond to the following:

kilowatt: $1 kW = 10^3 W$

megawatt: $1 MW=10^6 W$

gigawatt: $1 GW=10^9 W$

Using the list above, we can convert all the options into Watts:

A) $1 GW=1 \cdot 10^9 W$

B) $2 kW=2 \cdot 10^3 W$

C) $3 MW=3 \cdot 10^6 W$

D) $4 W$

Therefore, the smallest quantity is D) 4 Watts.

Zinaida [17]2 years ago

3 0

<span>D is the correct answer. A watt is the smallest amount of power. The prefix kilo means a thousand, mega means a million and giga means a billion, so, in increasing size: watt - kilowatt - megawatt - gigawatt.</span>

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A sodium has an atomic number of 11 and the atomic mass of 23. Determine the its proton, electrons, and neutrons

ioda

The mass number of an element tells us the number of protons AND neutrons in an atom (the two particles that have a measurable mass). Sodium has a mass number of 23amu. Since sodium has 11 protons, the number of neutrons must be 23 – 11 = 12 neutrons.

7 0

2 years ago

A friction force of 280 N exists between a cart and the path. If the force of reaction is 766 N, what is the minimum action forc

MatroZZZ [7]

force of friction on the cart is given as

$F_f = 280 N$

here we also know the reaction force due to surface

$R = 766 N$

so we can say reaction force is given as

$R = \sqrt{F_n^2 + F_f^2}$

$766 = \sqrt{F_n^2 + 280^2}$

$F_n^2 = 766^2 - 280^2$

$F_n = 713 N$

now by force balance we will say

$F_y + F_n = mg$

$F_y = mg - F_n$

$F_x = F_f$

also we know that

$F_f = \mu * F_n$

$280 = \mu * 713$

$\mu = 0.39$

now minimum force required to set this into motion

$F_{min} = \frac{\mu mg}{\sqrt{1 + \mu^2}}$

here we know that

$mg = F_n = 713 N$

$F_{min} = \frac{0.39* 713}{\sqrt{1 + 0.39^2}}$

$F_{min} = 259 N$

So it will require 259 N minimum force to move it

3 0

2 years ago

N experiment is performed in deep space with two uniform spheres, one with mass 27.0 and the other with mass 107.0 . They have e

Reptile [31]

Answer:

Explanation:

Apply the law of conservation of energy

$KE_i+PE_i=KE_f+PE_f$

$Gm_1m_2[\frac{1}{r_f} -\frac{1}{r_1} ]=\frac{1}{2} (m_1v_1^2+m_2v_2^2)$

from the law of conservation of the linear momentum

$m_1v_1=m_2v_2$

Therefore,

$Gm_1m_2[\frac{1}{r_f} -\frac{1}{r_1} ]=\frac{1}{2} (m_1v_1^2+m_2v_2^2)$

$=\frac{1}{2} [m_1v_1^2+m_2[\frac{m_1v_1}{m_2} ]^2]\\\\=\frac{1}{2} [m_1v_1^2+\frac{m_1^2v_1^2}{m_2} ]\\\\=\frac{m_1v_1^2}{2} [\frac{m_1+m_2}{m_2} ]$

$v_1^2=[\frac{2Gm_2^2}{m_1+m_2} ][\frac{1}{r_f} -\frac{1}{r_1} ]$

Substitute the values in the above result

$v_1^2=[\frac{2Gm_2^2}{m_1+m_2} ][\frac{1}{r_f} -\frac{1}{r_1} ]$

$=[\frac{2(6.67\times 10^-^1^1)(107)^2}{27+107} ][\frac{1}{26} -\frac{1}{41}] \\\\=1.6038\times 10^-^1^0\\\\v_1=\sqrt{1.6038\times 106-^1^0} \\\\=1.2664 \times 10^-^5m/s$

B) the speed of the sphere with mass 107.0 kg is

$v_2=\frac{m_1v_1}{m_2}$

$=[\frac{27}{107} ](1.2664 \times 10^-^5)\\\\=3.195\times 10^-^6m/s$

C) the magnitude of the relative velocity with which one sphere is

$v_r=v_1+v_2\\\\=1.2664\times 10^-^5+3.195\times10^-^6\\\\=15.859\times10^-^6m/s$

D) the distance of the centre is proportional to the acceleration

$\frac{x_1}{x_2} =\frac{a_1}{a_2} \\\\=\frac{m_2}{m_1} \\\\=3.962$

Thus,

$x_1=3.962x_2$

and

$x_2=0.252x_1$

When the sphere make contact with eachother

Therefore,

$x_1+x_2+2r=41\\x_1+0,252x_1+2r=41\\1.252x_1+2r=41\\x_1=32.747-1.597r$

And

$x_1+x_2+2r=41\\3.962x_2+x_2+2r+41\\4.962x_2+2r=41\\x_2=8.262-0.403r$

The point of contact of the sphere is

$32.747-1.597r=8.262-0.403r\\\\r=\frac{24.485}{1.194} \\\\=20.506m$

3 0

2 years ago

a scientists collects a core sample from 60 km deep in earth what will she most likley observe plz help taking a test

Svetradugi [14.3K]

Answer:

Explanation:

A scientist collects a core sample from 60 km deep in Earth. Which characteristic will she most likely observe in this sample? C. The sample mainly consists of ...

4 0

2 years ago

If a bouncing ball has a total energy of 20 J and a kinetic energy of 5 J, the ball’s potential energy is

navik [9.2K]

Answer:

15 and Increasing

Explanation:

Hope this helps

Have a wonderful day and many more to come

Alexis~

~A.K.A Moon~

7 0

1 year ago