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dezoksy [38]
3 years ago
5

A physics major is cooking breakfast when he notices that the frictional force between the steel spatula and the Teflon frying p

an is only 0.350 N. Knowing the coefficient of kinetic friction between the two materials (0.04), he quickly calculates the normal force. What is it (in N)?
Physics
1 answer:
wel3 years ago
8 0

Answer:

Normal force = 8.75 N

Explanation:

given,

frictional force between the steel spatula and the Teflon frying pan=0.350 N

coefficient of friction between material =0.04

normal force = ?

using formula,

Frictional force = coefficient of friction × normal force

normal\ force = \dfrac{Frictional\ force}{coefficient\ of\ friction}

normal\ force = \dfrac{0.350}{0.04}

Normal force = 8.75 N

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To solve this problem we will use the related concepts in Newtonian laws that describe the force of gravitational attraction. We will use the given value and then we will obtain the proportion of the new force depending on the Radius. From there we will observe how much the force of attraction increases in the new distance.

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Applying the new distance,

F = \frac{GMm}{(\frac{R}{2})^2}

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3 years ago
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Explanation:

7 0
3 years ago
A wire is stretched between two posts. Another wire is stretched between two posts that are four times as far apart. The tension
Elena-2011 [213]

Answer:

Therefore,

The speed of the wave on the longer wire is 95 m/s.

Explanation:

Given:

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v_{s}=190\ m/s

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L_{l}=4\times L_{s}

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v_{l}=?  Speed on the longer wire

Solution:

The speed of a pulse or wave on a string under tension can be found with the equation,

v=\sqrt{\dfrac{F_{T}\times L}{m}

Where,

F_{T} = Tension on the wire

L = Length of Sting

m = mass of String

So here we have,

F_{T} = same

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Therefore,

v_{s}=\sqrt{\dfrac{F_{T}\times L_{s}}{m} ......equation ( 1 )

And

v_{l}=\sqrt{\dfrac{F_{T}\times L_{l}}{m}  .......equation ( 2 )

Dividing equation 1 by equation 2 and on Solving we get

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Therefore,

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Therefore,

The speed of the wave on the longer wire is 95 m/s.

8 0
3 years ago
A ping pong ball has a mass of about 2.45 grams. Suppose that Forrest Gump hits the ball across the table with a speed of about
MrMuchimi

Answer:

0.0196J

Explanation:

KE equation is 1/2*m*v^2

when pluged in above numbers...

0.5*0.00245*4*4=0.0196J

6 0
3 years ago
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