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dezoksy [38]
3 years ago
5

A physics major is cooking breakfast when he notices that the frictional force between the steel spatula and the Teflon frying p

an is only 0.350 N. Knowing the coefficient of kinetic friction between the two materials (0.04), he quickly calculates the normal force. What is it (in N)?
Physics
1 answer:
wel3 years ago
8 0

Answer:

Normal force = 8.75 N

Explanation:

given,

frictional force between the steel spatula and the Teflon frying pan=0.350 N

coefficient of friction between material =0.04

normal force = ?

using formula,

Frictional force = coefficient of friction × normal force

normal\ force = \dfrac{Frictional\ force}{coefficient\ of\ friction}

normal\ force = \dfrac{0.350}{0.04}

Normal force = 8.75 N

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Answer:

3 every second

Explanation:

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3 years ago
What is the best definition for work?
olga55 [171]

Work is done when a force is in the same direction as the object moves.

Explanation:

The work done by a force in moving an object is given by the equation

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the directions of F and d

From the equation, we notice the following:

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Therefore, the correct answer is

Work is done when a force is in the same direction as the object moves.

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

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7 0
4 years ago
A car accelerates uniformly from rest to a speed of 56.8 km/h (15.8 m/s) in 10 s. find the distance the car travels during this
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3 years ago
A child accidentally drops a toy from his apartment window. It falls for 1.05 seconds. What is the velocity of the toy just befo
AVprozaik [17]

Sorry!

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6 0
3 years ago
Consider a uniformly volume‑charged sphere of radius R and charge Q . What is the electric potential on the surface of the spher
VARVARA [1.3K]

To solve this problem we will start by applying the given load ratio, and we will rely on the two types of distances given. Later we will use Gauss's law and through its integrals, in which it is equivalent to the potential we will obtain its value in the center of the sphere. Since it is uniformly charged we have to,

\frac{Q'}{Q} = \frac{4\pi r^3}{4\pi R^3}

Q' = \frac{r^3}{R^3} Q

By Gauss Law

\phi = E \cdot 4\pi r^2

Here, E is the electric Field and is equal to

E = \frac{Q'}{\epsilon_0}

For \epsilon_0 being the Permeability constant at free space

Replacing with the previous value we have,

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V = -\frac{Q}{8 \pi \epsilon_0 R}

6 0
3 years ago
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