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3 years ago

How is a reference point defined?

1 answer:

6 0

Simply be used as a reference point <span>to describe its position. a fact forming the basis of an evaluation or assessment; criterion. They had few cultural </span>reference points<span> in common.</span>

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A diver, of mass 40kg, climbs up to a diving platform 1.25m high. What’s her KE

Leona [35]

Explanation:

The formula for KE ( Kinetic Energy ) is : 1/2 mv²

Solution:

First we solve for v ( velocity ) using the formula 2gh, where g is gravity [ 9.8 m/s² ] and h is height [ 1.25 m ]

= 2 ( 9.8 m/s² × 1.25 m ) = 24.5 m/s

The velocity is 24.5 m/s.

Now solve for KE using the formula 1/2 mv²

= 1/2 ( 40 kg × 24.5m/s ² )

= 1/2 ( 40 kg × 600.25 )

= 1/2 ( 24,010 )

= 12,005 Joules

The diver's kinetic energy is 12,005 J.

6 0

2 years ago

A drill bit in a hand drill is turning at 1200 revolutions per minute (1200 rpm). Express this angular speed in radians per seco

ankoles [38]

Answer:

the answer will be about 126 rad/s

Explanation:

3 0

3 years ago

For a Soap Box racer, on a 302 m long course, start from rest, and accelerating at a constant 1.27 m/s?,

Naddik [55]

B Ya. cause A is no

7 0

3 years ago

Determine the force required to move a block if the coefficient of static friction of one block and the floor is 0.35 and the co

SashulF [63]

Answer:

32.5

Explanation:

Choose the normal force acting between the object and the ground. Let's assume a normal force of 250 N .

Determine the friction coefficient. ...

Multiply these values by each other: (250 N) * 0.13 = 32.5 N .

You just found the force of friction!

4 0

3 years ago

Bryan Allen pedaled a human-powered aircraft across the English Channel from the cliffs of Dover to Cap Gris-Nez on June 12, 197

Leno4ka [110]

(a) 3.58 km 45° south of east

The total displacement is given by:

$d=vt$

where

v is the average velocity

t is the time

The average velocity is:

v = 3.53 m/s

While we need to convert the time from minutes to seconds:

$t=169 min \cdot 60 s/min = 10140 s$

Therefore, the magnitude of the displacement is

$d=(3.53)(10140)=35794 m = 3.58 km$

And the direction is the same as the velocity, therefore 45° south of east.

(b) 5.53 m/s 90° south of east

The velocity of the air relative to the ground is

$v_a = 2.00 m/s$

and the direction is exactly opposite to that of Allen, so it is 45° north of west. Allen's velocity relative to the ground is

v = 3.53 m/s

So this must be the resultant of Allen's velocity relative to the air (v') and the air's speed ( $v_a$ ). Since these two vectors are in opposite direction, we have

$v= v'-v_a$

Therefore we find v', Allen's velocity relative to the air:

$v'=v+v_a = 3.53 + 2.00 = 5.53 m/s$

The direction must be measured relative to the air's reference frame. In this reference frame, Allen is moving exactly backward, so his direction will be 90° south of east.

(c) 56.1 km at 90° south of east.

Since Allen's velocity relative to the air is

v' = 5.53 m/s

Then the displacement of Allen relative to the air will be given by

$d'=v't$

and substituting,

$d'=(5.53)(10140)=56074 m = 56.1 km$

And the direction is the same as that of the velocity, therefore will be 90° south of east.

3 0

4 years ago