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enyata [817]
2 years ago
7

A 60-kg box is being pushed a distance of 6.2 m across the floor by a force P with arrow whose magnitude is 150 N. The force P w

ith arrow is parallel to the displacement of the box. The coefficient of kinetic friction is 0.21. Determine the work done on the box by each of the four forces that act on the box. Be sure to include the proper plus or minus sign for the work done by each force. (The floor is level and horizontal. Forces that act on the box: pushing force P, frictional force f, normal force N, and weight mg.)
Physics
1 answer:
Afina-wow [57]2 years ago
3 0

Answer:

Explanation:

mass of box, m = 60 kg

distance, d = 6.2 m

force, P = 150 N

coefficient of kinetic friction, μk = 0.21

work done by the gravitational force, Wg = Force x distance x cos 90

Wg = 0 J

Work done by the normal force, Wn = force x distance x Cos 90

Wn = 0 J

Work done by the friction force, Wf = - μk mg d

Wf = - 0.21 x 60 x 9.8 x 6.2 = - 765.58 J

Work done by the applied force, Wp = P x d

Wp = 150 x 6.2 = 930 J

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independent variable

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Answer:

In an elastic collision, the total kinetic energy is conserved, while in an inelastic collision, it is not

Explanation:

Let's define the two types of collision:

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2) the total kinetic energy of the system is NOT conserved

In an elastic collision, part of the total kinetic energy is lost (=converted into thermal energy) due to the presence of frictional forces. An example of inelastic collision is the accident between two cars, in which part of the energy is converted into heat.

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3 years ago
At the local playground, a 21-kg child sits on the right end of a horizontal teeter-totter, 1.8 m from the pivot point. On the l
Ksju [112]

Answer:

By convention a negative torque leads to clockwise rotation and a positive torque leads to counterclockwise rotation.

here weight of the child =21kgx9.8m/s2 = 205.8N

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net torque Tnet = -370.44+453 =82.56N , which is positive means counterclockwise rotation.

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Tnet = -370.44+377.5 = 7.06N-m , positive ,counterclockwise rotation.

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Tnet = -370.44+302 = -68.44N-m, negative,clockwise rotation.

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2 years ago
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Answer:

Explanation:

General Equation of SHM is given by

x=A\cos \omega t

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also it is given that Potential Energy(U) is equal to Kinetic Energy(K)

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at x=\frac{A}{\sqrt{2}}

velocity is v=\frac{A\omega}{\sqrt{2}}

6 0
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