La longitud <em>final</em> del puente de acero es 100.018 metros.
Asumamos que la dilatación <em>térmica</em> experimentada por el puente de acero es <em>pequeña</em>, de modo que podemos emplear la siguiente aproximación <em>lineal</em> para determinar la longitud <em>final</em> del puente de acero (
), en metros:
![L = L_{o}\cdot [1+\alpha\cdot (T_{f}-T_{o})]](https://tex.z-dn.net/?f=L%20%3D%20L_%7Bo%7D%5Ccdot%20%5B1%2B%5Calpha%5Ccdot%20%28T_%7Bf%7D-T_%7Bo%7D%29%5D)
(1)
Donde:
- Longitud inicial del puente, en metros. 
- Coeficiente de dilatación, sin unidad.
- Temperatura inicial, en grados Celsius.
- Temperatura final, en grados Celsius.
Si tenemos que 
, 
, 
y 
, entonces la longitud final del puente de acero es:
![L = (100\,m)\cdot [1+(11.5\times 10^{-6})\cdot (24\,^{\circ}C - 8\,^{\circ}C)]](https://tex.z-dn.net/?f=L%20%3D%20%28100%5C%2Cm%29%5Ccdot%20%5B1%2B%2811.5%5Ctimes%2010%5E%7B-6%7D%29%5Ccdot%20%2824%5C%2C%5E%7B%5Ccirc%7DC%20-%208%5C%2C%5E%7B%5Ccirc%7DC%29%5D)
La longitud <em>final</em> del puente de acero es 100.018 metros.
Para aprender más sobre dilatación térmica, invitamos cordialmente a ver esta pregunta verificada: brainly.com/question/24953416
Answer:
The radius of a chamber is 2.36 meters.
Explanation:
Given that,
The outer wall moves at a speed of 2.72 m/s.
Mass of the person, m = 75.1 kg
The person feels a force of 235 N force pressing against his back. The force acting on the person is centripetal force. It is given by the below formula :
r is the radius of a chamber
r = 2.36 meters
So, the radius of a chamber is 2.36 meters. Hence, this is the required solution.
The surface of the earth changes. Some changes are due to slow processes, such as erosion and weathering, and some changes are due to rapid processes, such as landslides, volcanic eruptions, and earthquakes.
