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Anuta_ua [19.1K]
3 years ago
7

An experimental spacecraft consumes a special fuel at a rate of 372 L/min. The density of the fuel is 0.730 g/mL and the standar

d enthalpy of combustion of the fuel is − 26.5kJ/g. Calculate the maximum power (in units of kilowatts) that can be produced by this spacecraft. 1kW = 1kJ/s?
Chemistry
1 answer:
Karolina [17]3 years ago
5 0

Explanation:

First, we will calculate fuel consumption is as follows.

         372 L/min \times 1000 ml/L \times 0.730 g/ml \times \frac{1}{60} min/s

           = 4526 g/s

Now, we will calculate the power as follows.

        Power = Fuel consumption rate × -enthalpy of combustion

                    = 4526 g/s \times -26.5 kJ/g

                    = 1.19 \times 10^{5} kW

Thus, we can conclude that maximum power (in units of kilowatts) that can be produced by this spacecraft is 1.19 \times 10^{5} kW.

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Determine the heat given off to the surroundings when 9.0 g of aluminum (fm = 26.98) reacts according to the equation 2al + fe2o
Akimi4 [234]

Hey there!:

Number of moles:

Molar Mass Al = 26.98 g/mol

n = mass / molar mass

n = 9.0 / 26.98

n = 0.3336 moles of Al

Given the reaction :

2 Al + Fe2O3 = Al2O3 + 2 Fe

From the equation, 2 moles of Al give off 849 kJ of heat :

Actual heat given off :

0.3336 / 2 * 849 =

0.3336 / 1698 = 1.4*10² Kj


Hope that helps!


8 0
2 years ago
OMG HELP!!!! I SUCK AT SCIENCE
Maksim231197 [3]
Organism are made up of organic molecules consisting of carbon, hydrogen, oxygen, nitrogen, sulfur, and phosphorus.

The answer is B.
6 0
2 years ago
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Water freezes in the cracks of rocks and then expands, breaking the rocks apart. This is an example of ___________ weathering. A
mr_godi [17]

The correct answer is: C) erosionl

7 0
2 years ago
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If 0.98 moles of BaCl2 are dissolved in enough water to make a 1.2-liter solution, what is the resulting molarity?
Svetradugi [14.3K]
<span>Correct Answer: <u>Option B i.e. 0.82 M </u>

Reason:
<em>Given:</em> number of moles of BaCl2 = 0.98, Volume of solution = 1.2 l

Molarity of solution = </span>\frac{\text{number of moles}}{\text{volume of solution (l)}}<span>
                               = </span>\frac{0.98}{1.21}<span>
                               = 0.82 M

 Thus, molarity of the solution is 0.82 M</span>
4 0
3 years ago
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At equilibrium, the concentrations in this system were found to be [N2]=[O2]=0.200 M and [NO]=0.600 M. N2(g)+O2(g)↽−−⇀2NO(g) If
cestrela7 [59]

Answer:

0.84M

Explanation:

Hello,

At first, the equilibrium constant should be computed because the whole situation is at the same temperature so it is suitable for the new condition, thus:

K_{eq}=\frac{[NO]^2_{eq}}{[N_2]_{eq}[O_2]_{eq}} \\K_{eq}=\frac{0.6^2}{0.2*0.2}\\ K_{eq}=9

Now, the new equilibrium condition, taking into account the change x, becomes:

9=\frac{[NO]^2_{eq}}{[N_2]_{eq}[O_2]_{eq}}\\9=\frac{[0.9+2x]^2}{[0.2-x][0.2-x]}

Nevertheless, since the addition of NO implies that the equilibrium is leftward shifted, we should change the equilibrium constant the other way around:

\frac{1}{9} =\frac{[N_2]_{eq}[O_2]_{eq}}{[NO]^2_{eq}}\\\frac{1}{9} =\frac{[0.2+x][0.2+x]}{[0.9-2x]^2}

Thus, we arrange the equation as:

\frac{1}{9} (0.9-2x)^2=(0.2+x)^2\\0.09-0.4x+4x^2=0.04+0.4x+x^2\\3x^2-0.8x+0.05=0\\x_1=0.06

Finally, the new concentration is:

[NO]_{eq}=0.9-0.06=0.84M

Best regards.

7 0
3 years ago
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