Answer:
The correct answer is that the polar bonds are altered and the boiling point is elevated.
Explanation:
In the case of table salt mixed with water, the sodium (Na) and chlorine (Cl) atoms initially bound together in the form of a crystal are dissolved by the water molecules.
The sodium and chlorine ions are mixed uniformly with the surrounding water molecules, so that the salt dissolves in the water, forming a homogeneous mixture. Water is a polar compound, so it easily dissolves polar substances such as salts.
This raises the boiling point of the water, as it is more difficult to break the bonds of the solution.
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It is 0.07 g for your answer
Answer: There is a couple different ways to determine if a bond is ionic or covalent.
Explanation:
By definition, an ionic bond is between a metal and a nonmetal, and a covalent bond is between 2 nonmetals. So you usually just look at the periodic table and determine whether your compound is made of a metal/nonmetal or is just 2 nonmetals Hope this helped !!!
Answer:
The differences in atmospheric pressure generate winds.
Explanation:
At the Equator, the sun warms the water and land more than it does the rest of the world. Warm equatorial air rises higher into the atmospher and migrates towards the poles. The complex relationships between fronts cause different types of winds and weather patterns.
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Answer:
The element is CARBON
The number 6 refers to the ATOMIC NUMBER
the numbers 12, 13, and 14 refer to the ATOMIC MASS
how many protons and neutrons are in the first isotope?
<u>6</u><u>. </u><u> </u><u> </u><u> </u><u> </u><u>6</u>
how many protons and neutrons are in the second isotope?
<u>6</u><u>. </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>7</u>
<u>how many protons and neutrons are in the </u><u>t</u><u>h</u><u>i</u><u>r</u><u>d</u><u> </u><u>isotope?</u>
<u>6</u><u>. </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>8</u>
<u>y</u><u>o</u><u>u</u><u> </u><u>a</u><u>r</u><u>e</u><u> </u><u>w</u><u>e</u><u>l</u><u>c</u><u>o</u><u>m</u><u>e</u><u> </u><u>:</u><u>)</u>