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pychu [463]
2 years ago
13

Waves on a swimming pool propagate at 0.720 m/s. You splash the water at one end of the pool and observe the wave go to the oppo

site end, reflect, and return in 31.0 s. How far away is the other end of the pool?
Physics
1 answer:
SVEN [57.7K]2 years ago
5 0

Answer:

11.16 m

Explanation:

total distance traveled by the wave = speed * time

                                                            = 0.720 m/s * 31.0 s

                                                            = 22.32 m

Since this is an echo back to the starting point then the length of the swimming pool must be half of the distance traveled.

length of swimming pool  =  22.32 m÷2 = 11.16 m

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Tim and Rick both can run at speed Vr and walk at speed Vw, with Vr > Vw.
miss Akunina [59]

Answer:

Δt =  \frac{2D}{Vw+Vr} - \frac{D}{2Vr} - \frac{D}{2Vw}

Explanation:

Hi there!

Using the equation of speed for the whole trip, we can obtain the time each one needed to cover the distance D.

The speed (v) is calculated by dividing the traveled distance (d) over the time needed to cover that distance (t):

v = d/t

Rick traveled half of the distance at Vr and the other half at Vw. Then, when v = Vr, the distance traveled was D/2 and the time is unknown, Δt1:

Vr = D/ (2 · Δt1)

For the other half of the trip the expression of velocity will be:

Vw = D/(2 · Δt2)

The total time traveled is the sum of both Δt:

Δt(total) = Δt1 + Δt2

Then, solving the first equation for Δt1:

Vr = D/ (2 · Δt1)

Δt1 = D/(2 · Vr)

In the same way for the second equation:

Δt2 = D/(2 · Vw)

Δt + Δt2 = D/(2 · Vr) + D/(2 · Vw)

Δt(total) = D/2 · (1/Vr + 1/Vw)

The time needed by Rick to complete the trip was:

Δt(total) = D/2 · (1/Vr + 1/Vw)

Now let´s calculate the time it took Tim to do the trip:

Tim walks half of the time, then his speed could be expressed as follows:

Vw = 2d1/Δt  Where d1 is the traveled distance.

Solving for d1:

Vw · Δt/2 = d1

He then ran half of the time:

Vr = 2d2/Δt

Solving for d2:

Vr · Δt/2 = d2

Since d1 + d2 = D, then:

Vw · Δt/2 +  Vr · Δt/2 = D

Solving for Δt:

Δt (Vw/2 + Vr/2) = D

Δt = D / (Vw/2 + Vr/2)

Δt = D/ ((Vw + Vr)/2)

Δt = 2D / (Vw + Vr)

The time needed by Tim to complete the trip was:

Δt = 2D / (Vw + Vr)

Let´s find the diference between the time done by Tim and the one done by Rick:

Δt(tim) - Δt(rick)

2D / (Vw + Vr) - (D/2 · (1/Vr + 1/Vw))

\frac{2D}{Vw+Vr} - \frac{D}{2Vr} - \frac{D}{2Vw} = Δt

Let´s check the result. If Vr = Vw:

Δt = 2D/2Vr - D/2Vr - D/2Vr

Δt = D/Vr - D/Vr = 0

This makes sense because if both move with the same velocity all the time both will do the trip in the same time.

8 0
3 years ago
Which one of Newton's Laws fits this statement:
BabaBlast [244]

Answer:

First Law

Explanation:

I learned this in 6th grade

5 0
3 years ago
On Earth, plasma exists in the ionosphere, in flames, and in chemical and nuclearexplosions. Matter in a controlled thermonuclea
nasty-shy [4]

The cost of developing thermonuclear power with plasmabe defended because D. It can provide an inexpensive power source.

<h3>How did the cost of developing thermonuclear power defended?</h3>

The  cost of developing thermonuclear power defended becvause we can see in the paragraph how it was told that the generation of ths power can be donee through the understanding of  the occurrence of plasmain nature,

It should be noted that this  thermonuclear power with plasmabe  posses the characteristics which make it to exist in the ionosphere, and it can be felt in the flames as well; as in the chemical and nuclearexplosions.

In conclusion the power can be seen as an inexpensive source power because the p[roduction of this power cn be found in most of the thing that can be found around us as discused above.

Therefore, option D is correct.

Read more about cost at:

brainly.com/question/25109150

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3 0
1 year ago
Nature of Sound Waves Sound is a wave that is created by ____________________ and propagated through a __________________ from o
natima [27]

Answer:

Nature of Sound Waves Sound is a wave that is created by <u>perturbations</u> and propagated through a <u>medium</u> from one location to another. Type of Wave: <u>longitudinal wave</u><u>.</u> A sound wave consists of a repeating pattern of high-pressure and low-pressure regions moving through a medium Sound needs a <u>medium of propagation</u> and a <u>disturbance.</u> Like any wave, the speed of a sound wave refers to how fast the disturbance is passed from particle to particle. Anatomy of a Wave:

3 0
3 years ago
25 mL of water is poured into a graduated cylinder. Several coins are dropped into the water, and the new volume is measured to
Arisa [49]
5 cubic cm is the answer
4 0
3 years ago
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