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hjlf
3 years ago
14

Do you think a colony on Mars should be nearer the northern or southern polar cap? Explain.

Chemistry
1 answer:
Ksju [112]3 years ago
7 0

Answer:

nearer to the north pole

Explanation:

because there is more water, which is basically gone everywhere else on Mars except for the south pole which has less water than the north pole

You might be interested in
Consider the Gibbs energies at 25 ∘C.
zysi [14]

Answer:

A)Δ​G​r​x​n​∘​=​55.7​k​J​/​m​o​l

B)Ksp=1.75×10^−10

C)Δ​G​r​x​n​∘​=​70.0​k​J​/​m​o​l

D)Ksp=5.45×10^−13

Explanation:

ΔGrxn∘=​Δ​G​f​,​p​r​o​d​u​c​t​s​∘​−​Δ​G​f​,​r​e​a​c​t​a​n​t​s​∘

To calculate for the

Ksp

of the dissolution reaction can be claculated

ΔGrxn∘=−RTlnKsp

where R is the proportionality constant equal to 8.3145 J/molK.

A)

Δ​G​r​x​n​∘​=​[​Δ​G​f​,​A​g​(​a​q​)​+​∘​+​Δ​G​f​,​C​l​(​a​q​)​−​∘​]​−​Δ​G​f​,

A​g​C​l​(​s​)​⇌​A​g​(​a​q​)​+​+​C​l​(​a​q​)​−

ΔG∘rxn=[77.1kJ/mol+(−131.2kJ/mol)]−(−109.8kJ/mol)

Δ​G​r​x​n​∘​=​55.7​k​J​/​m​o​l

b) Calculate the solubility-product constant of AgCI.

ΔGrxn∘=−RTlnKsp

55.7​k​J​/​m​o​l​=​−​(​8.3145​×​10​−​3​J​/​m​o​l​K​)​(​298.15​K)InKsp

Ksp=1.75×10^−10

c) Calculate

To calculate ΔG°rxn

for the dissolution of AgBr(s).

Δ​G​r​x​n​∘​=​[​Δ​G​f​,​A​g​(​a​q​)​+​∘​+​Δ​G​f​,​B​r​(​a​q​)​−​∘​]​−​Δ​G​f​,

Δ​G​r​x​n​∘​=​[​77.1​k​J​/​m​o​l​+​(​−​104.0​k​J​/​m​o​l​)​]​−​(​−96.90kj/mol

Δ​G​r​x​n​∘​=​70.0​k​J​/​m​o​l

d)To Calculate the solubility-product constant of AgBr.

ΔGrxn∘=−RTlnKsp

70.0kJ/mol=−(8.3145×10−3J/molK)(298.15K)lnKsp

70.0​k​J​/​m​o​l​=​−​(​8.3145​×​10​−​3​J​/​m​o​l​K​)​(​298.15​K

Ksp=5.45×10^−13

8 0
3 years ago
A reaction mechanism is defined as the sequence of reaction steps that define the pathway from reactants to products. Each step
olga55 [171]

Answer: (a) K *[A][B]^2

(b) The answer is B

Explanation:

A)

Step1:A+B<--> C (fast)

Step2: B+C→D(slow)

Rate depends on slowest step.

so,

rate = k' [B][C] ...eqn 1

But C is intermediate.so use step 1

Since 1st step is an equilibrium,

Kc = [C] /[A][B]

so,

[C] = Kc [A][B] ...eqn 2

put eqn 2 in eqn 1

rate = k' *[B] * Kc [A][B]

= k'Kc*[A][B]^2

= K *[A][B]^2 {writing k'Kc = K}

Answer: K *[A][B]^2

B)

Answer is B

Since rate depends on slowest step.

if slowest step is:

X2Y2+Z2→X2Y2Z+Z

then only,

rate= k[X2Y2][Z2]

Answer: B

6 0
3 years ago
How many electrons would be transferred in either a voltaic or electrolytic cell that uses the following half reactions
omeli [17]

Answer:

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

Explanation:

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V

Mg^{2+}(aq) + 2 e^- \rightarrow Mg (s),E^o = -2.37 V

The substance having highest positive reduction E^o potential will always get reduced and will undergo reduction reaction.

Reduction : cathode

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V..[1]

Oxidation: anode

Mg(s)\rightarrow Mg^{2+}(aq) + 2 e^-,E^o = 2.37 V..[2]

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

E^o_{cell}=-0.036V-(-2.37 V)=2.334 V

The overall reaction will be:

2 × [1] + 3 × [2] :

2Fe^{3+} (aq) + 3Mg(s)+6e^-\rightarrow 2Fe (s)+3Mg^{2+}(aq)+6e^-

Electrons on both sides will get cancelled :

2Fe^{3+} (aq) + 3Mg(s)\rightarrow 2Fe (s)+3Mg^{2+}(aq)

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

5 0
3 years ago
Please and thank you
Virty [35]

3.8mL of 0.42 phosphoric acid is required.

Reaction

2H3PO4 + 3CaCL3 → Ca3(PO)4 + 6HCl

moles CaCl2 =0.16 mol/L x0.010 L = 0.0016 mol

moles of H3Po4

= 0.0016mol of CaCl2 x 2 mole of H3PO4/3mole of CaCl2

= 0.00106 mol

V of H3PO4 = 0.0016/0.42 = 0.0038L = 3.8mL

V of H3PO4=3.8mL

To know more about calculation in milliliters refer to:-

brainly.com/question/23276655

#SPJ10

4 0
2 years ago
(GIVING BRAINLIEST) do what the following image says.
S_A_V [24]

Answer:

hope it helps.

<h3>stay safe healthy and happy.<u>.</u><u>.</u></h3>

7 0
3 years ago
Read 2 more answers
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