Answer:
[EtOH] = 2.2M and Wt% EtOH = 10.1% (w/w)
Explanation:
1. Molarity = moles solute / Volume solution in Liters
=> moles solute = mass solute / formula weight of solute = 9.8g/46g·mol⁻¹ = 0.213mol EtOH
=> volume of solution (assuming density of final solution is 1.0g/ml) ...
volume solution = 9.81gEtOH + 87.5gH₂O = 97.31g solution x 1g/ml = 97.31ml = 0.09731 Liter solution
Concentration (Molarity) = moles/Liters = 0.213mol/0.09731L = 2.2M in EtOH
2. Weight Percent EtOH in solution (assuming density of final solution is 1.0g/ml)
From part 1 => [EtOH] = 2.2M in EtOH = 2.2moles EtOH/1.0L soln
= {(2.2mol)(46g/mol)]/1000g soln] x 100% = 10.1% (w/w) in EtOH.
Answer:
1750L
Explanation:
Given
Initial Temperature = 25°C
Initial Pressure = 175 atm
Initial Volume = 10.0L
Final Temperature = 25°C
Final Pressure = 1 atm
Final Volume = ?
This question is an illustration of ideal gas law.
From the given parameters, the initial temperature and final temperature are the same; this implies that the system has a constant temperature.
As such, we'll make use of Boyle's Law to solve this;
Boyle's Law States that:
P₁V₁ = P₂V₂
Where P₁ and P₂ represent Initial and Final Pressure, respectively
While V₁ and V₂ represent Initial and final volume
The equation becomes
175 atm * 10L = 1 atm * V₂
1750 atm L = 1 atm * V₂
1750 L = V₂
Hence, the final volume that can be stored is 1750L
Answer:
1. Uniform, non visible
2. Visible, non uniform
3. Uniform, non visible
4. Visible, non uniform
5. Visible, non uniform
Explanation:
A heterogeneous mixture is simply any mixture that is not uniform in composition — it's a non-uniform mixture of smaller constituent parts. By contrast, a mixture that is uniform in composition is a homogenous mixture
visible state of matter is when you can easily difference two components of a mixture
non visible is when the state of the matter in the substance is not visible to the eye, it can't be differentiated
Answer: Semi-structured data is a type of data that has some consistent and definite characteristics. It does not confine into a rigid structure such as that needed for relational databases that which is why it will not fit into row and columns in a table .
Explanation:
