The graph above shows the progress of a chemical reaction. Based on the graph, which of the following is true?

Chemistry

2 answers:

rusak2 [61]3 years ago

4 0

In the given graph, it can be seen that the energy consumed by Reaction B is much lower compared to Reaction A during which both of the reaction reached the peak. This now suggest that because the reaction energy required for B is lowered, then the answer to this item is the second option.

algol [13]3 years ago

3 0

Answer: Reaction A is not enzyme-catalyzed, while reaction B is enzyme-catalyzed

Explanation:

The minimum energy required by the reactants to cross the energy barrier is called as activation energy. The use of enzyme lowers the activation energy as it takes the reaction through a different pathway which is lower in energy. Thus a enzyme catalyzed reaction has low activation energy as compared to a non catalyzed reaction.

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A solution is made by dissolving 4.87 g of potassium nitrate in water to a final volume of 86.4 mL solution. What is the weight/

lara31 [8.8K]

Answer:

A solution is made by dissolving 4.87 g of potassium nitrate in water to a final volume of 86.4 mL solution. The weight/weight % or percent by mass of the solute is :

2.67%

Explanation:

Note : Look at the density of potassium nitrate in water if given in the question.

You are calculating weight /Volume not weight/weight % or percent by mass of the solute

Here the weight/weight % or percent by mass of the solute is asked : So first convert the VOLUME OF SOLUTION into MASS

Density of potassium nitrate in water KNO3 = 2.11 g/mL

$density=\frac{mass}{volume}$

Density = 2.11 g/mL

Volume of solution = 86.4 mL

$2.11=\frac{mass}{86.4}$

$mass = 2.11\times 86.4$

$mass=182.3grams$

Mass of Solute = 4.87 g

Mass of Solution = 183.2 g

w/w% of the solute =

$= \frac{mass\ of\ solute}{mass\ of\ solution}\times 100$

$=\frac{4.87}{183.2}\times 100$

w/w%=2.67%

8 0

3 years ago

A molecular orbital that decreases the electron density between two nuclei is said to be ____.

nikklg [1K]

A molecular orbital that decreases the electron density between two nuclei is said to be antibonding.

The bonding orbital, which would be more stable and encourages the bonding of the two H atoms into $H_{2}$ , is the orbital that is located in a less energetic state than just the electron shells of the separate atoms. The antibonding orbital, which has higher energy but is less stable, resists bonding when it is occupied.

An asterisk (sigma*) is placed next to the corresponding kind of molecular orbital to indicate an antibonding orbital. The antibonding orbital known as * would be connected to sigma orbitals, as well as antibonding pi orbitals are known as $\pi$ * orbitals.