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Alexeev081 [22]
3 years ago
11

The graph above shows the progress of a chemical reaction. Based on the graph, which of the following is true?

Chemistry
2 answers:
rusak2 [61]3 years ago
4 0
In the given graph, it can be seen that the energy consumed by Reaction B is much lower compared to Reaction A during which both of the reaction reached the peak. This now suggest that because the reaction energy required for B is lowered, then the answer to this item is the second option. 
algol [13]3 years ago
3 0

Answer: Reaction A is not enzyme-catalyzed, while reaction B is enzyme-catalyzed

Explanation:

The minimum energy required by the reactants to cross the energy barrier is called as activation energy. The use of enzyme lowers the activation energy as it takes the reaction through a different pathway which is lower in energy. Thus a enzyme catalyzed reaction has low activation energy as compared to a non catalyzed reaction.

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What is the extended and shortened structural formula for 2-methylpentane
kotykmax [81]

The structural formula for 2-methylpentane is in Figure 1. It shows all the C-C and C-H bonds explicitly.

The bond-line formula for 2-methylpentane is in Figure 2. We assume that a carbon atom is at the ends and junctions of the lines. We do not show the H atom, but we mentally assume that there are enough to give each carbon a valence of four.

A condensed structural formula is designed to be typed <em>all on one line</em>. We could write the condensed structural formula for 2-methylpentane as either (CH₃)₂CH-CH₂-CH₂-CH₃ or CH₃CH(CH₃)CH₂CH₂CH₃.

The horizontal C-C bonds are <em>optional </em>— you can include or omit them as desired.

6 0
3 years ago
When 10 g of diethyl ether is converted to vapor at its boiling point, about how much heat is absorbed? (c4h10o, δhvap = 15.7 kj
vagabundo [1.1K]

Answer:

ΔH= 3KJ

Explanation:

The total heat absorbed is the total energy in the process, and that is in form of entalpy.

ΔH = q + ΔHvap, where q is the heat necessary for elevate the temperature of dietil ether. Suppose the initial temperature is room temperature (25ºC=298 K), then

q= 10g x2.261 J/gK x(310 K - 298K)= 271.32 J= 0.3 kJ

Then

ΔHvap = 10g C4H10O x (1 mol C4H10O/74.12 g C4H10O) x( 15.7 KJ/ 1 mol C4H10O) = 2.12 KJ

ΔH= 2.5KJ ≈ 3KJ

5 0
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"How many grams of CaCl2 would be dissolved in 1.0 L of a 0.10 M solution of CaCl2? "
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Answer:

2365 g

Explanation:

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