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Sonja [21]
4 years ago
12

Example of the word médium ?

Physics
1 answer:
Ira Lisetskai [31]4 years ago
4 0
I am the medium one that in the family
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Part A Magnetic field lines form closed loops Magnetic field lines form closed loops Around and through bar magnets. Through cur
alex41 [277]

Answer:

Magnetic field lines form closed loops around current carrying straight wires.

Explanation:

Magnetic field lines is known to form closed loop (which also serves as a bar magnet) around current carrying conductor in a magnetic field. This direction of the loop around the conductor either clockwise or anticlockwise will determine the direction of current in the conductor.

This directions can be determined using the Maxwell cockscrew or clenched fist rule.

According to clenched fist rule which states if the conductor is grasp with the right hand, the curled finger will point in the direction of the magnetic field and the thumb will point in the direction of the current.

Note that the magnetic field lines around the conductor also behaves like a bar magnet.

8 0
4 years ago
Salmon often jump waterfalls to reach their
erik [133]

Answer:

6.35 m/s

Explanation:

The motion of the salmon is equivalent to that of a projectile, which consists of two independent motions:

- A horizontal motion with constant speed

- A vertical motion with constant acceleration (g=-9.8 m/s^2, acceleration of gravity)

The horizontal velocity of the salmon is given by:

v_x = u cos \theta

where

u = ? is the initial speed

\theta=32^{\circ} is the angle of projection

Then the horizontal distance covered by the salmon after a time t is given by

d=v_x t =(u cos \theta) t

Or equivalently, the time taken to cover a distance d is

t=\frac{d}{u cos \theta} (1)

Along the vertical direction, the equation of motion is

h = (u sin \theta) t + \frac{1}{2}gt^2 (2)

where

u sin \theta is the initial vertical velocity

If we substitute (1) into (2), we get:

h = (u sin \theta) \frac{d}{cos \theta} + \frac{1}{2}g(\frac{d}{ ucos \theta})^2=d tan \theta + \frac{gd^2}{2u^2 cos^2 \theta}

We now that in order to reach the breeding grounds, the salmon must travel a distance of

d = 2.02 m

reaching a height of

h = 0.574 m

Substituting these data into the equation and solving for u, we find the initial speed that the salmon must have:

u =\sqrt{ \frac{gd^2}{2(h-d tan \theta) cos^2 \theta}}=\sqrt{\frac{(-9.8)(2.02)^2}{2(0.574-(2.02)(tan 32))(cos^2(32))}}=6.35 m/s

8 0
3 years ago
Please answer it I will mark it brainliest​
Margaret [11]

Explanation:

1) If you spot something you think might be hazardous in your workplace, report it to your employer and safety rep straight away. Your employer should then decide what harm the hazard could cause and take action to eliminate, prevent or reduce that harm. Read more about risk assessments .

2) Complex hazards are understood as various combinations of sources of hazards that lead to the accident occurrences. ... The term "natural-technological" applies to both human-induced intensification of natural risks and any accidents in the technosphere triggered by natural processes or phenomena.

3)Risk Evaluation : To determine who may be harmed. Risk Control : Taking preventive measures to control the impact of risk.

In general, to do an assessment, you should:

Identify hazards.

Determine the likelihood of harm, such as an injury or illness occurring, and its severity. ...

Identify actions necessary to eliminate the hazard, or control the risk using the hierarchy of risk control methods.

5 0
2 years ago
Read 2 more answers
M
cupoosta [38]

Answer:

<h3>The answer is 1.92 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 2.5 g

Volume = 1.3 cm³

We have

density =  \frac{2.5}{1.3}  \\  = 1.923076...

We have the final answer as

<h3>1.92 g/cm³</h3>

Hope this helps you

5 0
3 years ago
If an R = 1-kΩ resistor, a C = 1-μF capacitor, and an L = 0.2-H inductor are connected in series with a V = 150 sin (377t) volts
fgiga [73]

Answer

given,

R = 1-kΩ  = 1000 Ω

C = 1-μF

L = 0.2-H

V = V_max sin( ω t)

comparing

V = 150 sin ( 377 t)

ω = 377

\chi_c = \dfrac{1}{\omega C}

\chi_c = \dfrac{1}{377 \times 1 \times 10^{-6}}

\chi_c = 2652.5\Omega

\chi_L =377 \times 0.2

\chi_L =75.4\ \Omega

Impedance,

Z = \sqrt{R^2+(\chi_L-\chi_c)^2}

Z = \sqrt{1000^2+(75.4 -2652.5)^2}

Z = 2764.3 Ω

now,

V_{max} = 150 V

I_{max} = \dfrac{V}{Z}

I_{max} = \dfrac{150}{2764.3}

I_{max} = 0.0543

I_{max} = 54.3\ mA

3 0
3 years ago
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