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valkas [14]
3 years ago
7

The image below shows two opposite forces acting on a rope, what can we say is true about the affect of the forces on the rope?

Physics
2 answers:
Tamiku [17]3 years ago
8 0
It would be D) the rope is pulled to the right. This is because their is a greater force in that direction.
kykrilka [37]3 years ago
6 0

Answer: Option D.

Explanation: Here are two forces applied in opposite ends of the rope, both forces pulling the rope in one direction (opposite directions).

this means that the total force is the addition of the two forces (not exactly, because they are at different heights, but is a good approximation), the resultant force will be 175N - 75N = 100N

Here you can see that the force pulling right is almost 100N bigger than the other force, this means that factors like the difference in height actually don't matter, the difference in force is large enough to predict that the net force on the rope moves it to the right.

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If a set of scores has a mean of 100.00 and
AnnyKZ [126]

Answer:

Variance is 25

Explanation:

Recall that the standard deviation is defined as the square root of the variance. therefore, if you know the standard deviation (\sigma), square it and you get the variance:

Variance= \sigma^2\\Variance= 5^2= 25

5 0
3 years ago
Why is the energy stored in the wire per unit volume=1/2*strain*stress​
Sav [38]

Answer:

have tried it and the units end up being Nm^-2 (the unit of stress) however the unit for joules is Nm.

Source https://www.physicsforums.com/threads/why-does-1-2-stress-strain-equal-the-energy-stored-per-unit-volume-in-a-wire.565495/

6 0
3 years ago
A 1.1 kg hammer strikes a nail. Before the impact, the hammer is moving at 4.5 m/s; after the impact it is moving at 1.5 m/s in
Talja [164]

Answer:

132 N

Explanation:

Given that a  1.1 kg hammer strikes a nail. Before the impact, the hammer is moving at 4.5 m/s; after the impact it is moving at 1.5 m/s in the opposite direction. If the hammer is in contact with the nail for 0.025 s, what is the magnitude of the average force exerted by the hammer on the nail

From Newton 2nd law of motion,

Change in momentum = impulse.

Change in momentum = m( V - U )

Substitute all the parameters into the formula

Change in momentum = 1.1 ( 4.5 - 1.5 )

Change in momentum = 1.1 × 3

Change in momentum = 3.3 kgm/s

Impulse = Ft

That is,

Ft = 3.3

Substitute time t into the formula above

F × 0.025 = 3.3

F = 3.3 / 0.025

F = 132 N

Therefore, the magnitude of the average force exerted by the hammer on the nail is 132 N.

3 0
3 years ago
A square, single-turn coil 0.132 m on a side is placed with its plane perpendicular to a constant magnetic field. An emf of 27.1
marta [7]

Answer:

0.35 T

Explanation:

Side, a = 0.132 m, e = 27.1 mV = 0.0271 V, dA / dt = 0.0785 m^2 / s

Use the Faraday's law of electromagnetic induction

e = rate of change of magnetic flux

Let b be the strength of magnetic field.

e = dФ / dt

e = d ( B A) / dt

e = B x dA / dt

0.0271 = B x 0.0785

B = 0.35 T

6 0
3 years ago
An object's angular momentum is proportional to its __________. An object's angular momentum is proportional to its __________.
ozzi

An object's angular momentum is proportional to its moment of inertia.

Option D

<u>Explanation:</u>

Momentum is the measure of an object's movement with respect to its mass and velocity. So it is determined as the product of mass and velocity. An object moving in linear motion, will experience linear momentum.

Similarly, if an object moves in circular motion, then the momentum will be angular momentum. So it is measured as the product of moment of inertia with angular velocity.

              L = Iw

Here L is the angular momentum , I is the moment of inertia and ω is the angular velocity.

Thus, the angular momentum is directly proportional to the moment of inertia.

3 0
3 years ago
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