In this item, we are given with the x-component of the velocity. The y-component is equal to 0 m/s. The time it takes for it to reach the volume can be related through the equation,
d = V₀t + 0.5gt²
Substituting the known values,
225 = (0 m/s)(t) + (0.5)(9.8)(t²)
Simplifying,
t = 6.776 s
To determine the distance of the student from the edge of the building, we multiply the x-component by the calculated time.
range = (12.5 m/s)(6.776 s)
range = 84.7 m
<em>Answer: 84.7 m</em>
It is about 95%. The Wechsler Adult Intelligence Scale-IV is an IQ test that is given by therapists and measures worldwide scholarly working. It incorporates both verbal and nonverbal parts. The normal score for all tests and subtests is 100; therefore, a score of more than 100 is better than expected and beneath 100 is underneath normal.
Answer:
we can say here that | v² - u² | is the same for upward as for downward and change in the speed is different here so | v - u | same whenever rock travel up, down for same time and not same distances
Explanation:
given data
base = 3.60 m
speed u = 8 m/s
height = 1.70 m
to find out
check change in speed
solution
we know here formula for v that is
v² = u² - 2gh ............1 for upward speed
v² = u² + 2gh ............2 for projected speed
so here put all value and find v with h = 3.60 - 1.70 = 1.9 m
v² = 8² - 2(9.8) 1.9 = 26.76
v² = 8² + 2(9.8) 1.9 = 101.24
v = 5.173 m/s ..............3
v = 10.061 m/s ...................4
so change in speed form 3 and 4 equation
change in speed = v - u = 8 - 5.173 = 2.827 m/s .................5
change in speed = v - u = 10.061 - 8 = 2.061 m/s ..................6
so now we can say here that | v² - u² | is the same for upward as for downward and change in the speed is different here so | v - u | same whenever rock travel up, down for same time and not same distances
It’s a loose spherical structure which is located around the bulge and some of the disk
