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valkas [14]
3 years ago
7

The image below shows two opposite forces acting on a rope, what can we say is true about the affect of the forces on the rope?

Physics
2 answers:
Tamiku [17]3 years ago
8 0
It would be D) the rope is pulled to the right. This is because their is a greater force in that direction.
kykrilka [37]3 years ago
6 0

Answer: Option D.

Explanation: Here are two forces applied in opposite ends of the rope, both forces pulling the rope in one direction (opposite directions).

this means that the total force is the addition of the two forces (not exactly, because they are at different heights, but is a good approximation), the resultant force will be 175N - 75N = 100N

Here you can see that the force pulling right is almost 100N bigger than the other force, this means that factors like the difference in height actually don't matter, the difference in force is large enough to predict that the net force on the rope moves it to the right.

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How does light determine whether it acts as a particle or a wave?
pishuonlain [190]
Great question. Albert Einstein proved that light acts as both a particle and a wave in his 1905 paper. This is called wave-particle duality. 
With quantum mechanics, it is easy to prove that light behaves as both a particle and a wave. 
When UV light hits a metal surface, it causes an emission of electrons. This "photoelectric effect" proves how light behaves. 
5 0
2 years ago
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Where is the most energy transferred in a food web
Paladinen [302]

Answer:

The first trophic level of the food chain has the most energy.

8 0
3 years ago
An object falls from rest on a high tower and takes 5.0 s to hit the ground. Calculate the object's position from the top of the
Lena [83]

Answer:

After 1 sec = 4.9 m

After 2 sec = 19.6 m

After 3 sec = 44.1 m

After 4 sec =  78.4 m

After 5 sec = 122.5 m

Explanation:

After 1 sec:

<em>u=0m/s   t=1 s  a=9.8m/s²</em>

s = ut + (1/2)at²

=0(1) + (1/2)(9.8)(1²) = 4.9m

After 2 sec:

<em>u=0m/s   t=2 s  a=9.8m/s²</em>

s = ut + (1/2)at²

=0(2) + (1/2)(9.8)(2²) = 19.6m

After 3 sec:

<em>u=0m/s   t=3 s  a=9.8m/s²</em>

s = ut + (1/2)at²

=0(3) + (1/2)(9.8)(3²) = 44.1m

After 4 sec:

<em>u=0m/s   t=4 s  a=9.8m/s²</em>

s = ut + (1/2)at²

=0(4) + (1/2)(9.8)(4²) = 78.4m

After 5 sec:

<em>u=0m/s   t=5 s  a=9.8m/s²</em>

s = ut + (1/2)at²

=0(5) + (1/2)(9.8)(5²) = 122.5m

7 0
2 years ago
The membrane of a living cell can be approximated by a parallel-plate capacitor with plates of area 4.50×10−9 m2 , a plate separ
Marizza181 [45]

The energy stored in the membrane is 6.44\cdot 10^{-14} J

Explanation:

The capacitance of a parallel-plate capacitor is given by

C=\frac{k\epsilon_0 A}{d}

where

k is the dielectric constant of the material

\epsilon_0 is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

For the membrane in this problem, we have

k = 4.6

A=4.50\cdot 10^{-9} m^2

d=8.1\cdot 10^{-9} m

Substituting, we find its capacitance:

C=\frac{(4.6)(8.85\cdot 10^{-12})(4.50\cdot 10^{-9})}{8.1\cdot 10^{-9}}=2.26\cdot 10^{-11} F

Now we can find the energy stored: for a capacitor, it is given by

U=\frac{1}{2}CV^2

where

C=2.26\cdot 10^{-11} F is the capacitance

V=7.55\cdot 10^{-2} V is the potential difference

Substituting,

U=\frac{1}{2}(2.26\cdot 10^{-11} F)(7.55\cdot 10^{-2})^2=6.44\cdot 10^{-14} J

Learn more about capacitors:

brainly.com/question/10427437

brainly.com/question/8892837

brainly.com/question/9617400

#LearnwithBrainly

6 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs.
Brut [27]

Answer:

5 percent = normal matter

68 percent = dark energy

27 percent = dark matter

Explanation:

3 0
2 years ago
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