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valkas [14]
3 years ago
7

The image below shows two opposite forces acting on a rope, what can we say is true about the affect of the forces on the rope?

Physics
2 answers:
Tamiku [17]3 years ago
8 0
It would be D) the rope is pulled to the right. This is because their is a greater force in that direction.
kykrilka [37]3 years ago
6 0

Answer: Option D.

Explanation: Here are two forces applied in opposite ends of the rope, both forces pulling the rope in one direction (opposite directions).

this means that the total force is the addition of the two forces (not exactly, because they are at different heights, but is a good approximation), the resultant force will be 175N - 75N = 100N

Here you can see that the force pulling right is almost 100N bigger than the other force, this means that factors like the difference in height actually don't matter, the difference in force is large enough to predict that the net force on the rope moves it to the right.

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Find the momentum of a 25kg object traveling at a speed of 4m/s
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Answer:

100Kg.m/s

Explanation:

From the question, we obtained the following information:

M= Mass = 25kg

V = Velocity = 4m/s

Momentum =?

Momentum = MV = 25x4= 100Kg.m/s

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What does it mean for forces to be in equilibrium?.
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1. A pendulum has a period of 3 seconds. What's its frequency? 2. A pendulum has a frequency of 0.25 Hz. What's its period? 3. A
RideAnS [48]

Answer:

(1) 0.333 Hz

(2) 4 sec

(3) 2 sec, 0.5 Hz

Explanation:

(1) We have given time period of pendulum is 3 sec

So T = 3 sec

Frequency will be equal to f=\frac{1}{T}=\frac{1}{3}=0.333Hz

(2) Frequency of the pendulum is given f = 0.25 Hz

Time period is equal to T=\frac{1}{f}=\frac{1}{0.25}=4sec

(3) It is given that a pendulum makes 10 back and forth swings in 20 seconds

So time taken to complete 1 back and forth swings = =\frac{20}{10}=2sec

So time period T = 2 sec

Frequency will be equal to f=\frac{1}{T}=\frac{1}{2}=0.5Hz

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