Answer:
The magnitude of the acceleration is 1.2 × 10⁴ mi/h²
Explanation:
Hi there!
The acceleration is defined as the change in velocity in a time:
a = Δv / Δt
Where:
a = acceleration.
Δv = change in velocity = final velocity - initial velocity.
Δt = elapsed time.
In this case:
Initial velocity = 60 mi/h
final velocity = 50 mi/h
elapsed time = 3.0 s
Let´s convert the time unit into h:
3.0 s · 1 h /3600 s = 1/1200 h
Now, let´s calculate the acceleration:
a = Δv / Δt
a = (50 mi/h - 60 mi/h) / 1/1200 h
a = -1.2 × 10⁴ mi/h²
The magnitude of the acceleration is 1.2 × 10⁴ mi/h²
Newton’s second law of motion states that when a force acts on an object, the object’s acceleration is equal to the net force divided by the object’s mass, and is in the same direction as the net force.
<h2>Soccer player practices kicking the ball </h2>
The player has 15 meters per second ( m/s ) average velocity of the ball. In order to calculate, we know that the formula of calculating the velocity is velocity = displacement / time.
A player practices kicking the ball into the goal from halfway down the soccer field. Half displacement will be considered which is 45 meters and time interval is given which is 3 seconds. By putting values in the formula v = d / t ( 45 / 3 ) = 15, we get 15 m / s average velocity.
