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viva [34]
4 years ago
12

The smallest shift you can reliably measure on the screen is about 0.2 grid units. This shift corresponds to the precision of po

sitions measured with the best Earth-based optical telescopes. If you cannot measure an angle smaller than this, what is the maximum distance at which a star can be located and still have a measurable parallax
Physics
1 answer:
creativ13 [48]4 years ago
3 0

Answer:

The distance is  d = 1.5 *10^{15} \ km

Explanation:

From the question we are told that

        The smallest shift is d = 0.2 \ grid \ units

Generally a grid unit is  \frac{1}{10} of  an arcsec

  This implies that  0.2 grid unit is  k =  \frac{0.2}{10} = 0.02  \  arc sec

The maximum distance at which a star can be located and still have a measurable parallax is mathematically represented as

           d =  \frac{1}{k}

substituting values

           d =  \frac{1}{0.02}

           d = 50 \ parsec

Note  1 \ parsec  \ \to 3.26 \ light \ year \ \to 3.086*10^{13} \ km

So  d = 50 * 3.08 *10^{13}

     d = 1.5 *10^{15} \ km

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Read 2 more answers
PLZ HELP ON #22-26!!!! <br><br>Please explain why and how you got your answer.
AleksAgata [21]
22. a - (vf^2 - vi^2)/(2d) 
a = (0 - 23^2)/(170) 
a = -3.1 m/s^2

23. Find the time (t) to reach 33 m/s at 3 m/s^2
33-0/t = 3 
33 = 3t 
t = 11 sec to reach 33 m/s^2
Find the av velocuty: 33+0/2 = 16.5 m/s
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24. The sprinter starts from rest. The average acceleration is found from: 
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25. Acceleration of car = v-u/t = 0ms^-1-21.0ms^-1/6.00s = -3.50ms^-2
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26. Assuming a constant deceleration of 7.00 m/s^2
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This is the speed pf the car just bore braking. 

I hope this helps!! 

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3 years ago
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