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kozerog [31]
3 years ago
7

A concentrated solution of compound A in the same solvent was diluted from an initial volume of 2.00 mL to a fi nal volume of 25

.00 mL and then had an absorbance of 0.733. What is the concentration of A in the concentrated solution?
Chemistry
1 answer:
Andre45 [30]3 years ago
4 0

Answer:

The concentration of A in the concentrated solution is 0.05864

Explanation:

Given

Volume 1 = V1 = 2.00mL

Volume 2 = V2 = 25.00mL

Absorbance 1 = A1 = ?

Absorbance 2 = A2 = 0.733

Beer's law states that the concentration of a chemical solution is directly proportional to its absorbance.

i.e.

V = kA where V = Volume (Concentration)

A = Absorbance

k = Constant

Make k the subject of formula

k = V/A

V1/A1 = V2/A2

Make A1 the subject of the formula

A1 = V1 * A2/V2

Substitute the values of V1, A2 and V2

A1 = 2 * 0.733/25

A1 = 0.05864

So, the concentration of A in the concentrated solution is 0.05864

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The density of aluminum is 2.70 g/cm3. Apiece of aluminum foil that is 1000 cm on each side has a mass of 440. mg. How thick is
MissTica
Mass/volume = density
mass = (440 mg)*(1g)/(1000mg) = 0.440g
volume = (1000cm)(1000cm)(t)
where t = thickness
density = 2.70 g/cm^3 = (0.440g)/((1000cm)(1000cm)(t))

multiply both sides by 't' and divide both sides by (2.70g/cm^3)

t = (0.440) / ((1000cm)(1000cm)(2.70)) = 1.629x10^-7 cm

t = (1.629 x 10^-7 cm)*(1000000 micrometers)/(1 cm) = 0.1629 micrometers

Answer is t = 0.1629 micrometers
8 0
3 years ago
Some commercially available algaecides for swimming pools claim to contain 7% copper. Could the method used in this experiment t
AleksandrR [38]

Answer:

Explanation:

  1. 7% copper implies 7 w/v%(weight/volume %) of copper. This implies a 100 mL algaecide arrangement contains 7 grams of copper.  
  2. Henceforth we have a thought of the measure of copper that ought to be available in a given example of algaecide.  
  3. Indeed, even a 1 mL algaecide test is sufficient to discover the percentage of copper in it.  
  4. so a 25mL sample of algaecide must have around 1.75g of copper.
4 0
3 years ago
Calculate the solubility of copper(II) hydroxide, Cu(OH)2, in g/L​
Oduvanchick [21]

Answer:

Ksp = [ Cu+² ] [ OH-] ²

molar mass Cu(oH )2 ==> M= 63.546 (1) + 16 (2) + 1 (2) = 97.546 g/mol

Ksp = [ Cu+² ] [ OH-] ²

Ksp [ cu (OH)2 ] = 2.2 × 10-²⁰

|__________|___<u>Cu</u><u>+</u><u>²</u><u> </u>__|_<u>2</u><u>OH</u><u>-</u>____|

|<u>Initial concentration(M</u>)|___<u>0</u>__|_<u>0</u>______|

<u>|Change in concentration(M)</u>|_<u>+S</u><u> </u>|__<u>+2S</u>__|

|<u>Equilibrium concentration(M)|</u><u>_S</u><u> </u><u>_</u><u>|</u><u>2S___</u><u>|</u>

Ksp = [ Cu+² ] [ OH-] ²

2.2 ×10-²⁰ = (S)(2S)²= 4S³

s =  \sqrt[3]{ \frac{2.2 \times  {10}^{ - 20} }{4} }  = 1.8 \times  {10}^{ - 7}

S = 1.8 × 10-⁷ M

The molar solubility of Cu(OH)2 is 1.8 × 10-⁷ M

Solubility of Cu (OH)2 =

Cu (OH)2 =  \frac{1.8 \times  {10}^{ - 7} mol \:Cu (OH)2 }{1L}  \times  \frac{97.546 \: g \: Cu (OH)2}{1 \: mol \: Cu (OH)2}  \\  = 1.75428 \times 10 ^{ - 5}

<h3>Solubility of Cu (OH)2 = 1.75428 × 10 -⁵ g/ L</h3>

I hope I helped you^_^

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Answer:

On treatement of 2 -with hydrogen gas and lindlar catalyst, the major product obtained is cis-2butene.

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2 years ago
The activity of tocopherols is destroyed by
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<span>A. Commercial cooking
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