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kozerog [31]
3 years ago
7

A concentrated solution of compound A in the same solvent was diluted from an initial volume of 2.00 mL to a fi nal volume of 25

.00 mL and then had an absorbance of 0.733. What is the concentration of A in the concentrated solution?
Chemistry
1 answer:
Andre45 [30]3 years ago
4 0

Answer:

The concentration of A in the concentrated solution is 0.05864

Explanation:

Given

Volume 1 = V1 = 2.00mL

Volume 2 = V2 = 25.00mL

Absorbance 1 = A1 = ?

Absorbance 2 = A2 = 0.733

Beer's law states that the concentration of a chemical solution is directly proportional to its absorbance.

i.e.

V = kA where V = Volume (Concentration)

A = Absorbance

k = Constant

Make k the subject of formula

k = V/A

V1/A1 = V2/A2

Make A1 the subject of the formula

A1 = V1 * A2/V2

Substitute the values of V1, A2 and V2

A1 = 2 * 0.733/25

A1 = 0.05864

So, the concentration of A in the concentrated solution is 0.05864

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In the lewis structure of ch3oh, how many bonding pairs of electrons are there?
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Calculate the mole fraction of the ionic species kcl in the solution.
sp2606 [1]

The question is incomplete, here is the complete question:

Calculate the mole fraction of the ionic species KCl in the solution A solution was prepared by dissolving 43.0 g of KCl in 225 g of water.

<u>Answer:</u> The mole fraction of KCl in the solution is 0.044

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For water:</u>

Given mass of water = 225 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{225g}{18g/mol}=12.5mol

  • <u>For KCl:</u>

Given mass of KCl = 43 g

Molar mass of KCl = 74.55 g/mol

Putting values in equation 1, we get:

\text{Moles of KCl}=\frac{43g}{74.55g/mol}=0.577mol

Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

  • <u>For KCl:</u>

Moles of KCl = 0.577 moles

Total moles = [0.577 + 12.5] = 13.077 moles

Putting values in above equation, we get:

\chi_{(KCl)}=\frac{0.577}{13.077}=0.044

Hence, the mole fraction of KCl in the solution is 0.044

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