Answer:
Copper(II) sulphate – sodium hydroxide reaction
The reaction between copper(Il) sulphate and sodium hydroxide solutions is a good place to start. If you slowly add one to the other while stirring, you will get a precipitate of copper(II) hydroxide, Cu(OH)2.
B is the answer , i got you
Answer:
0.50 M
Explanation:
Given data
- Mass of sodium sulfate (solute): 7.1 g
- Volume of solution: 100 mL
Step 1: Calculate the moles of the solute
The molar mass of sodium sulfate is 142.04 g/mol. The moles corresponding to 7.1 grams of sodium sulfate are:
Step 2: Convert the volume of solution to liters
We will use the relation 1 L = 1000 mL.
Step 3: Calculate the molarity of the solution
Ok they are both can formed by the same high pressure system . the heat waves are extended periods of above-normal temperatures . but the cold wave is an extended periods of below normal temperatures
Answer:
0.05257 L/s
Explanation:
Step 1: Given data
The school uses 1200 gallons/day
Step 2: Convert "gal/day" to "L/day"
We will use the conversion factor 1 gal = 3.785 L.
1200 gal/day × (3.785L/gal) = 4542 L/day
Step 3: Convert "L/day" to "L/s"
We will use the following conversion factors:
4542 L/day × (1 day/24 h) × (1 h/3600 s) = 0.05257 L/s
