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JulijaS [17]
3 years ago
12

Single Replacement: HCI + Zn

Physics
1 answer:
Kay [80]3 years ago
4 0

During a single replacement, the Zn and H will switch places. That means the product formed will be ZnCl and H2.

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The white dwarf that remains when our sun dies will be mostly made of
expeople1 [14]

Answer:

Carbon and oxygen

Explanation:

White dwarfs are the stars which have used all their hydrogen and helium fuel and now exists with only carbon and oxygen in their core. Their size reduces up to one hundredth times of the size of their sun in early stages and yet they possess the same mass.  

Due to loss of fuels and impact of gravity, a young star collapses on itself leading to formation of dwarf star.

 

7 0
3 years ago
Kepler's 3 laws with formula centerpital<br> forces
madreJ [45]

Answer:

Kepler's Third Law

T = 2 π r 3 G M E . T = 2 π r 3 G M E . For an ellipse, recall that the semi-major axis is one-half the sum of the perihelion and the aphelion. For a circular orbit, the semi-major axis (a) is the same as the radius for the orbit.

6 0
3 years ago
Steve is whirling a rubber cork, tied with a string to his finger, over his head as shown in the figure. The motion of the cork
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The tension in the string corresponds to the gravitational attraction between the Sun and any planet.

6 0
3 years ago
Read 2 more answers
An unpolarized beam of light with an intensity of 4000 W/m2 is incident on two ideal polarizing sheets. If the angle between the
erastova [34]

Answer:

The intensity is  I_2  =  1654 \ W/m^2

Explanation:

From the question we are told that

    The intensity of the unpolarized light is  I_o  =  4000 \ W/m^2

    The  angle between the ideal polarizing sheet is  \theta =  0.429 \ rad = 0.429 *  57.296 =  24.58^o

Generally the intensity of  light emerging from the first polarizer is mathematically represented as

               I_2  =  \frac{I_o}{2}

substituting values

               I_1  =  \frac{4000}{2}

                I_1  =  2000 \ W/m^2

Then the intensity of  incident light emerging from the second polarizer is mathematically represented by Malus law as

                 I_2  =  I_1  cos^2 (\theta )

substituting values

                I_2  = 2000  * [cos (24.58)]^2

                I_2  =  1654 \ W/m^2

4 0
3 years ago
3) Find the missing parts of the triangle (angle and/or sides).<br>​
oee [108]

Answer:

44.4°

Explanation:

Use SOH-CAH-TOA.

Sine = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Tangent = Opposite / Adjacent

You're given an unknown angle, the adjacent side to that angle, and the hypotenuse.  So use cosine.

Cosine = Adjacent / Hypotenuse

cos A = 10 / 14

A = cos⁻¹(5/7)

A ≈ 44.4°

8 0
3 years ago
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