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OLga [1]
2 years ago
15

3. Two cars, both with a mass of 500 kg, are traveling down a road. The first car has a velocity of 65 m/s east and the second c

ar has a velocity of 85 m/s west. (Chapter 2 – Pages 54-55) a. Calculate the momentum of both cars showing the appropriate equation from your textbook and your work with units in order to receive credit. b. Which car has the larger momentum? Explain how you know.
Physics
1 answer:
fenix001 [56]2 years ago
5 0

Answers:

a) Momentum for Car 1: p_{1}=32500kg.m/s East

   Momentum for Car 2:p_{2}=42500kg.m/s West

b) Car 2 has the greater momentum

Explanation:

a) The linear momentum p is given by the following equation:

p=m.v (1)

Where m is the mass of the object and v its velocity.

In this case both cars have a mass of 500kg but different velocities (v_{1}=65m/s east for car 1 and v_{2}=85m/s west for car 2).

For Car 1:

p_{1}=m.v_{1} (2)

p_{1}=(500kg)(65m/s) (3)

p_{1}=32500kg.m/s (4)

For Car 2:

p_{2}=m.v_{2} (5)

p_{2}=(500kg)(85m/s) (6)

p_{2}=42500kg.m/s (7)

b) Having the result of the lineal momentum for both cars, we know Car 2 has the larger momentum, this can be known because Car 2 has a greater velocity.

So, if momentum is directly proportional to the mass and the velocity of the object, both objects have the same mass but different velocities; the object with greater mass will have the greater momentum.

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A light bulb emits light that travels uniformly in all directions. Detailed measurements show that at a distance of 56 m from th
vladimir1956 [14]

Complete question:

A light bulb emits light that travels uniformly in all directions. Detailed measurements show that at a distance of 56 m from the bulb, the amplitude of the electric field is 3.78 V/m. What is the average intensity of the light?

Answer:

The average intensity of the light is 0.02 W/m²

Explanation:

Given;

Amplitude of the electric field, E₀ = 3.78 V/m

The average intensity of the light is calculated as follows;

I_{avg} = \frac{c\epsilon_0 E_0^2}{2}

where;

I_{avg} is the average intensity of the light

c is speed of light = 3 x 10⁸ m/s

I_{avg} = \frac{(3\times 10^8)(8.85 \times 10^{-12}) (3.78)^2}{2} \\\\I_{avg} = 0.01897 \ W/m^2\\\\I_{avg} = 0.02 \ W/m^2

Therefore, the average intensity of the light is 0.02 W/m²

4 0
2 years ago
true or false Newtons's First Law states "Acceleration depends on the mass of the object and the unbalanced force applied"
babunello [35]
False, his first law states: An object that's in motion will remain in motion at a constant velocity unless it's acted on by an unbalanced force.

8 0
3 years ago
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Why might a wine glass survive a fall onto a
Alina [70]

Answer:

5

Explanation:

8 0
2 years ago
Does the temperature of a material always increase as it is heated? Explain briefly.
Lerok [7]
To answer your question, no,
temperature does not always increase as it is heated. Adding heat does not always increase the temp.
For example, when water is boiling, adding heat does not increase the temperature. This occurs at the boiling temp of every substance that can vaporize. 

Hope this explanation was helpful and brief! :)
6 0
3 years ago
The mass of Earth is 5.972 x 1024 kg and its orbital radius is an average of 1.496 x 1011 m. Calculate its linear momentum, give
Anna007 [38]

Answer: its linear momentum is 1.78 × 10²⁹ kg.m/s

Explanation:

Given that;

mass of Earth m =  5.972 x 10²⁴ kg

radius r = 1.496 x 10¹¹ m

period t = 3.15 x 10⁷ s

now we know that Earth rotates in a circular path so the distance travelled per rotation is;

d = 2πr we substitute

d = 2π × 1.496 x 10¹¹ m

= 9.4 × 10¹¹ m

Now formula for speed v is;

v = d/t

we substitute

v = 9.4 × 10¹¹ m / 3.15 x 10⁷ s

v = 2.98 × 10⁴ m/s

now we determine the linear momentum p

linear momentum p = mv

we substitute

p = (5.972 x 10²⁴ kg) × (2.98 × 10⁴ m/s)

p = 1.78 × 10²⁹ kg.m/s

Therefore its linear momentum is 1.78 × 10²⁹ kg.m/s

8 0
3 years ago
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