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OLga [1]
3 years ago
15

3. Two cars, both with a mass of 500 kg, are traveling down a road. The first car has a velocity of 65 m/s east and the second c

ar has a velocity of 85 m/s west. (Chapter 2 – Pages 54-55) a. Calculate the momentum of both cars showing the appropriate equation from your textbook and your work with units in order to receive credit. b. Which car has the larger momentum? Explain how you know.
Physics
1 answer:
fenix001 [56]3 years ago
5 0

Answers:

a) Momentum for Car 1: p_{1}=32500kg.m/s East

   Momentum for Car 2:p_{2}=42500kg.m/s West

b) Car 2 has the greater momentum

Explanation:

a) The linear momentum p is given by the following equation:

p=m.v (1)

Where m is the mass of the object and v its velocity.

In this case both cars have a mass of 500kg but different velocities (v_{1}=65m/s east for car 1 and v_{2}=85m/s west for car 2).

For Car 1:

p_{1}=m.v_{1} (2)

p_{1}=(500kg)(65m/s) (3)

p_{1}=32500kg.m/s (4)

For Car 2:

p_{2}=m.v_{2} (5)

p_{2}=(500kg)(85m/s) (6)

p_{2}=42500kg.m/s (7)

b) Having the result of the lineal momentum for both cars, we know Car 2 has the larger momentum, this can be known because Car 2 has a greater velocity.

So, if momentum is directly proportional to the mass and the velocity of the object, both objects have the same mass but different velocities; the object with greater mass will have the greater momentum.

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In most circumstances, the normal force acting on an objectand
Lynna [10]

Answer:

Normal Force is usually perpendicular to the movement and static friction usually means that there is no movement.

Explanation:

The work donde by any force on an object is equal to the displacement of the object multiplied by the component of the force that is in the direction of the displacement.

Normal force is usually perpendicular to the movement, so there is no component in the direction of the displacement. This is why it is zero in most circumstances.

<em>Static</em> friction on the other hand, usually means that there is no movement at all (it's static). It means that there is no displacement between the object and ground (in most cases). If there is no displacement, there is no work.

4 0
3 years ago
Suppose the total momentum of two masses before a collision is 100 kg m/s. What is the total momentum of the two masses after th
soldier1979 [14.2K]
No, momentum is conserved so:
momentum before=momentum after
it is C. 100 kg m/s
4 0
3 years ago
In order to go in a circle at a constant speed an object needs
maxonik [38]

Answer:

So for an object moving in a circle, there must be an inward force acting upon it in order to cause its inward acceleration. This is sometimes referred to as the centripetal force requirement. The word centripetal (not to be confused with the F-word centrifugal) means center seeking.

Explanation:

hope this helps

3 0
3 years ago
(a) Calculate the magnitude of the gravitational force exerted by Mars on a 80 kg human standing on the surface of Mars. (The ma
andrew11 [14]

Answer:

a) F=1.044\times 10^9\ N

b)F'=1.044\times 10^9\ N

c) F_p=1.0672\times10^{-7}\ N

d) Treat the humans as though they were points or uniform-density spheres.

Explanation:

Given:

  • mass of Mars, M=6.4\times 10^{23}\ kg
  • radius of the Mars, r=3.4\times 10^{6}\ m
  • mass of human, m=80\ kg

a)

Gravitation force exerted by the Mars on the human body:

F=G.\frac{M.m}{r^2}

where:

G=6.67 \times 10^{-11}\ m^3.kg^{-1}.s^{-2} = gravitational constant

F=6.67\times10^{-11}\times \frac{6.4\times 10^{23}\times 80}{(3.4\times 10^{6})^2}

F=1.044\times 10^9\ N

b)

The magnitude of the gravitational force exerted by the human on Mars is equal to the force by the Mars on human.

F'=F

F'=1.044\times 10^9\ N

c)

When a similar person of the same mass is standing at a distance of 4 meters:

F_p=6.67\times10^{-11}\times \frac{80\times 80}{4}

F_p=1.0672\times10^{-7}\ N

d)

The gravitational constant is a universal value and it remains constant in the Universe and does not depends on the size of the mass.

  • Yes, we have to treat Mars as spherically symmetric so that its center of mass is at its geometric center.
  • Yes, we also have to ignore the effect of sun, but as asked in the question we have to calculate the gravitational force only due to one body on another specific body which does not brings sun into picture of the consideration.
4 0
3 years ago
Hi my name is Lexi I'm looking for some friends on here! I I go to Baldwin arts and academics. so can you PLZ be my friend on he
katrin [286]

Answer:

You should use this for work related questions :/

8 0
3 years ago
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