1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anton [14]
4 years ago
14

A scientist’s curiosity is a legitimate driving force of scientific endeavor

Physics
1 answer:
igomit [66]4 years ago
5 0
True . Your statement is correct
You might be interested in
A uniform ladder 5.0 m long rests against a frictionless, vertical wall with its lower end 3.0 m from the wall. The ladder weigh
dem82 [27]

Answer:

Explanation:

a )

Reaction force of the ground

R = mg

= 160 N

Maximum friction force possible

= μ x R

= μ x 160

= .4 x 160

= 64 N .

b )

 160 N will act at middle point . 740N will act at distance of 3 / 5 m from the wall ,

Taking moment about top point of ladder

160 x 1.5 + 740 x 3/5 + f x 4 = 900 x 3

240 + 444 + 4f = 2700

f = 504 N

c )

Let x be the required distance.  

Taking moment about top point of ladder

160 x 1.5 + 740 x 3 x / 5 + .4 x 900 x 4  = 900 x 3  ( .4 x 900 is the maximum friction possible )

240 + 444 x + 1440  = 2700

x = 2.3  m

so man can go upto 2.3 at which maximum friction acts .

8 0
4 years ago
Which of the following are density labels? <br> a. Kg/L <br> b. g/m <br> c. g/mL <br> d. cm/g
bearhunter [10]
Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. It is a property that can be used to describe a substance.<span> </span><span>It has standard units of kg/m^3 or g/mL. So, the best answer is option C.</span>

4 0
3 years ago
Read 2 more answers
A car begins at rest at a stoplight. After the light turn green, the car begins to accelerate 5 m/s2 over the span of 3.6 second
trasher [3.6K]

Answer:

d=9m

Explanation:

5 0
3 years ago
The average distance between the variable scores and the mean in a set of data is the __________. A. range B. standard deviation
ololo11 [35]
The average distance between the variable scores and the mean in a set of data is the standard deviation.

6 0
3 years ago
Read 2 more answers
A student is using a frequency generator set to 440 Hz. Another student has an identical generator playing an unknown frequency.
Anna71 [15]

Answer:

The unknown frequency is either 438 Hz or 442 Hz.

Explanation:

The frequency of a beat heard when two sounds with frequencies f₁ and f₂, are played simultaneously, is simply the difference between two frequencies.

b = |f₁ - f₂|

b = 2 Hz

f₁ = 440 Hz

f₂ = ?

440 - f₂ = 2 or 440 - f₂ = -2

f₂ = 438 Hz or 442 Hz

The unknown frequency is either 438 Hz or 442 Hz.

Hope this Helps!!!

5 0
3 years ago
Other questions:
  • What is the frequency of an event?
    9·2 answers
  • The action force is the balloon pushing the air out. What is the magnitude of the reaction force of the air pushing on the ballo
    9·2 answers
  • A child, who is 45 m from the bank of a river, is being carried helplessly downstream by the river's swift current of 1.0 m/s. A
    12·1 answer
  • A student is planning an investigation on the properties of different types of matter. What would be the best method to find the
    8·2 answers
  • Which type of hearing problem can be reduced which ordinary hearing aids
    5·1 answer
  • What best defines work?
    11·1 answer
  • The volume of the vessel is reduced twice,and the number of molecules is reduced three times.How the pressure will change gas?​
    7·1 answer
  • What is the term used for sediments building up at the mouth of the river? (Hint: think New Orleans)
    10·1 answer
  • The magnitude of each force is 208 N the force on the right is applied at an angle 36° and the mass of the block is 17 kg the co
    11·1 answer
  • During which moon phase do spring tides occur?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!