Answer:
The laminar flow is generally given in high viscosity fluids such as honey or oil, it has the characteristic of flowing in an orderly manner, the walls of the tube have a zero speed while in the center it has a maximum speed.
turbulent flow is characterized by fluid velocity vectors presenting themselves in a disorderly manner and in all directions.
I attached the drawings for the velocity profile in laminar and turbulent flow.
A compass is a analog sensor
Answer: Your question has some missing figures so kindly plug in the values into the solution provided to get the exact amount of money saved
answer : Electric power generated = 216 * 10^6 kJ
money saved = $0.XY * 60000 kwh
Explanation:
<u>Calculating the amount of electric power generated by wind turbine</u>
power generated = ( 30 * 2000 ) kWh = 60000 kWh
Electric energy generated = 60000 kWh * 3600 kJ = 216 * 10^6 kJ
<u>Calculate money saved by school per year </u>
$0.XY * 60000 kwh
Answer:
engine B is more efficient.
Explanation:
We know that Carnot cycle is an ideal cycle for all working heat engine.In Carnot cycle there are four processes in which two are constant temperature processes and others two are isentropic process.
We also kn ow that the efficiency of Carnot cycle given as follows
![\eta =1-\dfrac{T_1}{T_2}](https://tex.z-dn.net/?f=%5Ceta%20%3D1-%5Cdfrac%7BT_1%7D%7BT_2%7D)
Here temperature should be in Kelvin.
For engine A
![\eta =1-\dfrac{T_1}{T_2}](https://tex.z-dn.net/?f=%5Ceta%20%3D1-%5Cdfrac%7BT_1%7D%7BT_2%7D)
![\eta =1-\dfrac{273+20}{520+273}](https://tex.z-dn.net/?f=%5Ceta%20%3D1-%5Cdfrac%7B273%2B20%7D%7B520%2B273%7D)
![\eta =0.63](https://tex.z-dn.net/?f=%5Ceta%20%3D0.63)
For engine B
![\eta =1-\dfrac{T_1}{T_2}](https://tex.z-dn.net/?f=%5Ceta%20%3D1-%5Cdfrac%7BT_1%7D%7BT_2%7D)
![\eta =1-\dfrac{273+20}{820+273}](https://tex.z-dn.net/?f=%5Ceta%20%3D1-%5Cdfrac%7B273%2B20%7D%7B820%2B273%7D)
![\eta =0.73](https://tex.z-dn.net/?f=%5Ceta%20%3D0.73)
So from above we can say that engine B is more efficient.