Answer:
a)
b)
c)
Explanation:
From the question we are told that:
Beaker Mass
Liquid Mass
Balance D:
Mass
Balance E:
Mass
Volume
a)
Generally the equation for Liquid's density is mathematically given by
b)
Generally the equation for D's Reading at A pulled is mathematically given by
m_d = mass of block - mass of liquid displaced
c)
Generally the equation for E's Reading at A pulled is mathematically given by
The question is not complete. We are supposed to find the average value of v_o.
Answer:
v_o,avg = 0.441V
Explanation:
Let t1 and t2 be the start and stop times of the output waveforms. Thus, from the diagram i attached, using similar triangles, we have;
3/(T/4) = 0.7/t1
So, 12/T = 0.7/t1
So, t1 = 0.7T/12
t1 = 0.0583 T
Also, from symmetry of triangles,
t2 = T/2 - t1
So, t2 = T/2 - 0.0583 T
t2 = 0.4417T
Average of voltage output is;
v_o,avg = (1/T) x Area under small triangle
v_o,avg = (1/T) x (3 - 0.7) x (T/4 - t1)
v_o,avg = (1/T) x (2.3) x (T/4 - 0.0583 T)
v_o,avg = (1/T) x 2.3 x 0.1917T
T will cancel out to give;
v_o,avg = 0.441V
Answer:
And we can find this probability with this difference:
And then we can conclude that the probability that someone watches between 3 and 5 hours a day is approximately 0.591 using a normal distribution
Explanation:
For this case we can define the random variable X as "hours that a person watches television". For this case we don't have the distribution for X but we have the following parameters:
We can assume that the distribution for X is normal
And we want to find this probability:
And we can use the z score formula given by:
And we can find the z score for each limit and we got:
And we can find this probability with this difference:
And then we can conclude that the probability that someone watches between 3 and 5 hours a day is approximately 0.591 using a normal distribution