Answer:
A: density and gravity
Explanation:
The Froude Number is defined as a dimensionless parameter that measures the ratio of the force of inertia on an element of fluid to the weight of the fluid element. In simple terms, it's the force of inertia divided by the gravitational force.
Froudes number is usually expressed as;
Fr = v/√(gd)
Where;
Fr = froude number
v = velocity
g = gravitational acceleration = specific weight/density
d = depth of flow
Now, to calculate the corresponding speed and force in the prototype, it means we have to use equal froude number and thus this will mean that it has to be dominated by gravity and density.
Answer:
Explanation:
So therefore new Resistance R¹ = R/49
Resistance of a wire
R = ¶ * L/A
Where ¶ = resistivity of wire
L = length of wire
A = cross sectional area of wire
So therefore if the wire is cut into 7 equal lengths and joined together to form one with new Resistance R¹
So new length L¹ = 1L/7
New A¹ = 7A
So therefore R¹ = ¶ (L/7) /(7A)
So R¹ = ¶*L/A(49)
Since R = ¶L/A
So therefore R¹ = R/49
Answer:
if you are interested in working for a company then you should opt for c). Company Site
Explanation:
Industries can have the same scope of work but every company has their own way of achieving objectives. You should learn about the company, its job functions and the specific sector you're interested in. Review the current projects they are working on (specific to your job function), and how you can benefit the company on those projects.
Answer:
61257.6 kW per day
Explanation:
The rating of the refrigerator is given as : 709 w
This means the power consumption is 709 joules per second
The operating time is given as 10 hours.
Change hours to second as
1 hour = 3600 seconds
10 hours = 36000 seconds
Apply the rating as;
709 w = 1 s
? = 36000 seconds
perform cross product to get;
709 * 36000= 25524000 w
25524000 = 25524kW
For a day, 24 hours will be;
25524 kW = 10 hours
? =24 hours
={24*25524}/10 = 61257.6 kW per day
Answer:
0.0432 m^3/s
Explanation:
Internal diameter of smaller pipes = 2.5 cm = 0.025 m
pipa wall thickness = 3 mm = 0.003 m
internal diameter of larger pipes = 8 cm = 0.8 m
velocity of region between smaller and larger pipe = 10 m/s
Calculate discharge in m^3/s
First we calculate the area of the smaller pipe
A = 
= 
= 0.00023571 m^2
next we calculate area of fluid between the smaller pipes and larger pipe
A = ![[\frac{\pi }{4} D^{2} _{L} ] - 3(A_{s})](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%5Cpi%20%7D%7B4%7D%20D%5E%7B2%7D%20_%7BL%7D%20%20%5D%20-%203%28A_%7Bs%7D%29)
= ![[ \frac{\pi }{4} (0.08 )^2 - 3 ( 0.00023571 )]](https://tex.z-dn.net/?f=%5B%20%5Cfrac%7B%5Cpi%20%7D%7B4%7D%20%280.08%20%29%5E2%20-%203%20%28%200.00023571%20%29%5D)
= [ 0.00502857 - 0.00070713 ]
= 0.00432144 m^2
hence the discharge in m^3/s
Q = AV
= 0.00432144 * 10
= 0.0432 m^3/s
