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<span>The sum of the speeds is 9.44 m/s + 9.44 m/s which is 18.88 m/s
Note that the sum of the speeds of the two stones is always 18.88 m/s because as the upward moving stone loses speed, the downward moving stone gains the same amount of speed each unit of time.
We can find the time for the stones to meet.
t = d / v
t = 5.39 m / 18.88 m/s
t = 0.285487 seconds
We can use the upward moving stone to find the height y.
y = v0 t + (1/2) a t^2
y = (9.44 m/s)(0.285487 s) - (1/2) (9.8 m/s^2) (0.285487 s)^2
y = 2.30 m
The two stones cross paths a height of 2.30 meters above the base of the cliff.</span>
First, we assume this as an ideal gas so we use the equation PV=nRT. Then, we use the conditions at STP that would be 1 atm and 273.15 K. We calculate as follows:
PV= nRT
PV= mRT/MM
1 atm (.245 L) =1.30(0.08206)(273.15) / MM
MM = 118.94 g/mol <--- ANSWER
Answer:
995 N
Explanation:
Weight of surface, w= 4000N
Gravitational constant, g, is taken as 9.81 hence mass, m of surface is W/g where W is weight of surface
m= 4000/9.81= 407.7472
Using radius of orbit of 6371km
The force of gravity of satellite in its orbit,
Where and
F= 995.01142 then rounded off
F=995N
Complete Question
The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a rather average star in the distant Garbanzo Galaxy. A scouting party sets out to explore. The party's leader–a physicist, naturally–immediately makes a determination of the acceleration due to gravity on the Pink Planet's surface by means of a simple pendulum of length 1.08m. She sets the pendulum swinging, and her collaborators carefully count 101 complete cycles of oscillation during 2.00×102 s. What is the result? acceleration due to gravity:acceleration due to gravity: m/s2
Answer:
The acceleration due to gravity is
Explanation:
From the question we are told that
The length of the simple pendulum is
The number of cycles is
The time take is
Generally the period of this oscillation is mathematically evaluated as
substituting values
The period of this oscillation is mathematically represented as
making g the subject of the formula we have
Substituting values