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crimeas [40]
3 years ago
6

Howell Corporation's activity-based costing system has three activity cost pools--Machining, Setting Up, and Other. The company'

s overhead costs, which consist of equipment depreciation and indirect labor, are allocated to the cost pools in proportion to the activity cost pools' consumption of resources.
Equipment depreciation (total) $ 28,800
Indirect labor (total) $ 7,310
Distribution of Resource Consumption Across Activity Cost Pools

Machining Setting Up Other
Equipment depreciation 0.20 0.50 0.30
Indirect labor 0.30 0.30 0.40
Costs in the Machining cost pool are assigned to products based on machine-hours (MHs) and costs in the Setting Up cost pool are assigned to products based on the number of batches. Costs in the Other cost pool are not assigned to products.

MHs Batches
Product S4 15,300 300
Product C0 8,100 1,400
Total 23,400 1,700
Additional data concerning the company's products appears below:

Product S4 Product C0
Sales (total) $ 78,900 $ 72,900
Direct materials (total) $ 21,900 $ 23,600
Direct labor (total) $ 42,600 $ 26,300
Required:

a. Assign overhead costs to activity cost pools using activity-based costing.

Activity Cost Pools
Machining Setting Up Other Total
Equipment depreciation
Indirect labor
Total
b. Calculate activity rates for each activity cost pool using activity-based costing.

Activity Cost Pools Activity Rate
Machining per MH
Setting up per batch
c. Determine the amount of overhead cost that would be assigned to each product using activity-based costing.

Amount of Overhead Cost
Product S4
Product C0
d. Determine the product margins for each product using activity-based costing.

Product Margin
Product S4
Product C0
Physics
1 answer:
german3 years ago
4 0

Answer:

Assign overhead costs to activity cost pools

see the attached file below

Explanation:

Download docx
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a) Q1=Q2=480μC   V1=240V   V2=60V

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Explanation:

Let C1 = 2μC  and  C2=8μC

For part (a) of this problem, we know that charge in a series circuit, is the same in C1 and C2. Having this in mind, we can calculate equivalent capacitance first:

C=\frac{1}{\frac{1}{C1} +\frac{1}{C2} } = 1.6\mu C

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For part (b), the capacitors are in parallel now. In this condition, the voltage is the same for both capacitors:

V1=V2   So,  \frac{Q1}{C1} = \frac{Q2}{C2}

Total charge is the same calculated for part (a), so:

\frac{Qt - Q2}{C1} = \frac{Q2}{C2}   Solving for Q2:

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For part (c), both capacitors would discharge, since their total voltage of 300V would by applied to a wire (R=0Ω). There would flow a huge amount of current for a short period of time, and capacitors would be completely discharged. Q1=Q2=0C  V1=V2=0V

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