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velikii [3]
4 years ago
13

2. Mrs. Roberts, in a diabetic coma, has just been admitted to Noble Hospital. Her blood pH indicates that she is in severe acid

osis, and measures are quickly instituted to bring her blood pH back within normal limits. (a) Define pH and note the normal pH of blood. (b) Why is severe acidosis a problem?
Chemistry
1 answer:
UNO [17]4 years ago
8 0

Answer:

Explanation:

a) The pH can be define as the measurement of the hydrogen or hydroxide ion concentration in a solution. The pH for blood is 7.4. In severe acidosis condition the pH of blood is 7.35 or lower.

b) Severe acidosis is a condition which is caused due to the overproduction of acid and building up of acid in the blood. This occurs due to the excessive loss of bicarbonate from the blood or buildup of carbon dioxide  in the blood. This leads to poor functioning of the lungs and depressed breathing.

The severe acidosis is critical condition because because it can adversely affect the cell membranes, muscle contraction, and function of the kidneys and neural activity of the body.  

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A student measures the absorbance of a sample of red dye #3 using a spectrophotometer. If the absorbance is measured as 0.468, w
Gre4nikov [31]

Answer:

5.88 μM is the concentration of red dye in the sample.

Explanation:

Absorbance is defined s capacity of a substance to absorb a light of a specified wavelength.It is calculated by using Beer-Lambert Law:

A=\epsilon lc

A = absorbance

\epsilon = Molar absorptivity

c = concentration

l =  Length of the solution through which light passes

Given, A = 0.468, l = d = 1.00 cm,c = ?

\epsilon =7.96\times 10^4 M^{-1} cm^{-1}

A=\epsilon lc

0.468=7.96\times 10^4 M^{-1} cm^{-1}\times 1.00 cm\times c

c=5.8793\times 10^{-6} mol/L=5.8793 mol/(\mu L)\approx 5.88mol/(\mu L)

(1 L= 1,000,000 \mu L)

5.88 μM is the concentration of red dye in the sample.

5 0
3 years ago
Tyrel is learning about a certain kind of metal used to make satellites. He learns that infrared light is absorbed by the metal,
VARVARA [1.3K]

Answer:

If it receives energy faster than it can radiate/convect/conduct it away, its temperature will increase. It does not matter.

Explanation:

6 0
3 years ago
Read 2 more answers
Be sure to answer all parts. Write the balanced equations corresponding to the following rate expressions: a) rate = − 1 3 Δ[CH4
Alinara [238K]

Answer : The balanced equations will be:

(a) 3CH_4+2H_2O+CO_2\rightarrow 4CH_3OH

(b) 2N_2O_5\rightarrow 2N_2+5O_2

(c) 2H_2+2CO_2+O_2\rightarrow 2H_2CO_3

Explanation :

The general rate of reaction is,

aA+bB\rightarrow cC+dD

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}

\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}

\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}

\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}

Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

Now we have to determine the balanced equations corresponding to the following rate expressions.

(a) Rate=-\frac{1}{3}\frac{d[CH_4]}{dt}=-\frac{1}{2}\frac{d[H_2O]}{dt}=-\frac{d[CO_2]}{dt}=+\frac{1}{4}\frac{d[CH_3OH]}{dt}

The balanced equations will be:

3CH_4+2H_2O+CO_2\rightarrow 4CH_3OH

(b) Rate=-\frac{1}{2}\frac{d[N_2O_5]}{dt}=+\frac{1}{2}\frac{d[N_2]}{dt}=+\frac{1}{5}\frac{d[O_2]}{dt}

The balanced equations will be:

2N_2O_5\rightarrow 2N_2+5O_2

(c) Rate=-\frac{1}{2}\frac{d[H_2]}{dt}=-\frac{1}{2}\frac{d[CO_2]}{dt}=-\frac{d[O_2]}{dt}=+\frac{1}{2}\frac{d[H_2CO_3]}{dt}

The balanced equations will be:

2H_2+2CO_2+O_2\rightarrow 2H_2CO_3

4 0
3 years ago
How many milliliters (mL) of 0.610 M NaOH solution are needed to neutralize 20 mL of a 0.245 M H2SO4 solution?
jenyasd209 [6]
There is to know the b
6 0
3 years ago
How many atoms are in 6.3 moles of lead
densk [106]

Answer:

3.79 x 10²⁴atoms

Explanation:

Given parameters:

Number moles of lead  = 6.3moles

Unknown:

Number of atoms  = ?

Solution:

To solve this problem,

              1 mole of a substance contains  6.02 x 10²³ atoms

            6.3 mole of Pb  will contain 6.3  x 6.02 x 10²³ = 3.79 x 10²⁴atoms

4 0
3 years ago
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