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3 years ago

9

How are electromagnetic waves used in bar-code scanners?

1 answer:

Natali5045456 [20]3 years ago

3 0

Answer:

A barcode reader (or barcode scanner) is an optical scanner that can read printed barcodes, decode the data contained in the barcode and send the data to a computer. Like a flatbed scanner, it consists of a light source, a lens and a light sensor translating for optical impulses into electrical signals.

Explanation:

A barcode reader (or barcode scanner) is an optical scanner that can read printed barcodes, decode the data contained in the barcode and send the data to a computer. Like a flatbed scanner, it consists of a light source, a lens and a light sensor translating for optical impulses into electrical signals.

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Calculate the density of Saturn. Show your work. How does it compare with the density of water? Explain how this can be.

stepladder [879]

Answer:

The density of Saturn is 686.81 kg/m³.

Explanation:

Mass of Saturn, $m=5.68\times 10^{26}\ kg$

Volume of Saturn, $V=8.27\times 10^{23}\ m^3$

Density of Saturn is given by its mass divided by its volume i.e.

$d=\dfrac{m}{V}$

$d=\dfrac{5.68\times 10^{26}}{8.27\times 10^{23}}$

$d=686.81\ kg/m^3$

So, the density of Saturn is 686.81 kg/m³.

The density of water is 1000 kg/m³. It is clear that the density of Saturn is less than water.

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3 years ago

What does DRAG mean in American science?

mestny [16]

DRAG is the sum of all the aerodynamic or hydronamic forces in the direction of the external fluid flow.

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4 years ago

A scientific ____ is a rule used to describe a pattern seen in nature, not an explanation of why that pattern might occur.

Fynjy0 [20]

D. sequence because a pattern is like a sequence and that doesn't explain why that pattern would occur.

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3 years ago

In college softball, the distance from the pitcher's mound to the batter is 43 feet. If the ball leaves the bat at 110 mph , how

Tomtit [17]

Explanation:

It is given that,

The distance from the pitcher's mound to the batter is 43 feet, d = 43 feet = 0.00814 miles

Speed with which ball leaves the ball, v = 110 mph

Let t is the time elapses between the hit and the ball reaching the pitcher. It is given by :

$t=\dfrac{d}{v}$

$t=\dfrac{0.00814}{110}$

t = 0.000074 hours

or

t = 0.2664 seconds

So, the time between the hit and the ball reaching the pitcher is 0.2664 seconds. Hence, this is the required solution.

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3 years ago

What happens to centripetal acceleration as the radius of curvature decreases and the speed is constant, and why

lutik1710 [3]

It increases, because the centripetal acceleration is inversely proportional to the radius of the curvature.

Hopr it helps :)

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3 years ago