maximum allowed value of the speed in roller coaster is given as
![v = 20 m/s](https://tex.z-dn.net/?f=v%20%3D%2020%20m%2Fs)
now from kinematics we can say
![v^2 - v_i^2 = 2 a s](https://tex.z-dn.net/?f=v%5E2%20-%20v_i%5E2%20%3D%202%20a%20s)
here initial speed will be
![v_i = 0](https://tex.z-dn.net/?f=v_i%20%3D%200)
acceleration is due to gravity
![a = 9.8 m/s^2](https://tex.z-dn.net/?f=a%20%3D%209.8%20m%2Fs%5E2)
now we can use this to find the height
![20^2 - 0^2 = 2 * 9.8* h](https://tex.z-dn.net/?f=20%5E2%20-%200%5E2%20%3D%202%20%2A%209.8%2A%20h)
![400 = 19.6 *h](https://tex.z-dn.net/?f=400%20%3D%2019.6%20%2Ah)
![h = 20.4 m](https://tex.z-dn.net/?f=h%20%3D%2020.4%20m)
so maximum allowed height will be 20.4 m
Explanation:
Given parameters:
Energy input = 130000J
Energy output = 53000J
Unknown:
Efficiency of the conversion = ?
Solution:
Efficiency is the percentage of work output to work input;
Mathematically;
Efficiency = Energy output/ Energy input x 100
Efficiency = 53000/130000 x 100 = 40.8%
Answer:
![\huge\boxed{m = 70 \ kg}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7Bm%20%3D%2070%20%5C%20kg%7D)
Explanation:
<u>Given Data:</u>
Momentum = P = 700 kg m/s
Velocity = v = 10 m/s
<u>Required:</u>
Mass = m = ?
<u>Formula:</u>
P = mv
<u>Solution:</u>
m = P / v
m = 700 / 10
m = 70 kg
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AnonymousHelper1807</h3>
Answer:
Explanation:
Heat and temperature are related to each other, but are different concepts. Heat is the total energy of molecular motion in a substance while temperature is a measure of the average energy of molecular motion in a substance. ... Temperature does not depend on the size or type of object
Answer:
2.771208%
Explanation:
= Change of volume
= Initial volume
= Change in temperature = (0.3-1050)
= Volumetric coefficient of thermal expansion = ![-26.4\times 10^{-6}\ /K](https://tex.z-dn.net/?f=-26.4%5Ctimes%2010%5E%7B-6%7D%5C%20%2FK)
Volumetric expansion of heat is given by
![\frac{\Delta V}{V_0}=\beta \Delta T\\\Rightarrow \frac{\Delta V}{V_0}=-26.4\times 10^{-6}\times (0.3-1050)\\\Rightarrow \frac{\Delta V}{V_0}=0.02771208](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20V%7D%7BV_0%7D%3D%5Cbeta%20%5CDelta%20T%5C%5C%5CRightarrow%20%5Cfrac%7B%5CDelta%20V%7D%7BV_0%7D%3D-26.4%5Ctimes%2010%5E%7B-6%7D%5Ctimes%20%280.3-1050%29%5C%5C%5CRightarrow%20%5Cfrac%7B%5CDelta%20V%7D%7BV_0%7D%3D0.02771208)
Finding percentage
![\frac{\Delta V}{V_0}=0.02771208\times 100=2.771208\%](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20V%7D%7BV_0%7D%3D0.02771208%5Ctimes%20100%3D2.771208%5C%25)
The ratio of change of volume to initial volume is 2.771208%