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3 years ago

Identify where the solid would be found after distillation is complete.

Physics

1 answer:

dimaraw [331]3 years ago

8 0

Bottom of the distillation flask

Explanation:

The solid in the mixture to be separate would be found at the bottom of the distillation flask.

Distillation is a separation technique for differentiating the components of mixtures based on the differences in their boiling points.

Distillation is used to recover solvents from solution.
The solutes are then left behind in the flask as the solvent boils out as vapor.
The solution is boiled in a distillation flask to vaporize the solvent.
The vapor is made to condense back into liquid by means of a condenser.
The pure liquid called distillate is collected in the receiver.
The solute which is the solid remains in the distillation flask

learn more:

Heterogeneous mixtures brainly.com/question/1446244

Pure substances brainly.com/question/1832352

#learnwithBrainly

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The transfer of heat by the movement of a fluid is called

ikadub [295]

Answer:Convection

Explanation:

Convection is the heat transfer procedure by the movement of liquid or gas molecules. It is a combination of diffusion and bulk motion of molecules. Near the surface of the liquid diffusion process dominates while at certain height bulk motion of liquid dominates.

Convection can be

Natural
Forced

Natural : Natural convection occurs due to density differences

Forced: Force convection occurs when we apply external heat source.

8 0

3 years ago

A race car is accelerating at 5m/s and then speeds up to a final velocity of 12 m/s if the race car driver finished this let of

noname [10]

Answer:

the acceleration of the car is 1.167 m/s²

Explanation:

Given;

initial velocity of the race car, u = 5 m/s

final velocity of the race car, v = 12 m/s

time to finish the race, t = 6 s

The acceleration of the car is calculated as;

a = (v - u) / t

a = (12 - 5) / (6)

a = 1.167 m/s²

Therefore, the acceleration of the car is 1.167 m/s²

3 0

2 years ago

Read 2 more answers

A mass of 6 kg with initial velocity 16 m/s travels through a wind tunnel that exerts a constant force 8 N for a distance 1.6 m.

strojnjashka [21]

Answer:

$D=99.4665307m \approx 99.5m$

Explanation:

From the question we are told that

Mass $m=6kg$

Velocity of mass $V_m=16$

Force of Tunnel $F_t=8N$

Length of Tunnel $L_t=1.6$

Height of frictional incline $H_i=2.9$

Angle of inclination $\angle =16 \textdegree$

Acceleration due to gravity $g=9.8m/s^2$

First Frictional surface has a coeﬃcient $\alpha_1 =0.21\ for\ d_c=1$

Second Frictional surface has a coeﬃcient $\alpha _2=0.1$

Generally the initial Kinetic energy is mathematically given by

$K.E=\frac{1}{2}mv^2$

$K.E=\frac{1}{2}(6)(16)^2$

$K.E=768$

Generally the work done by the Tunnel is mathematically given as

$w_t=F_t*d_t$

$w_t=8*1.6$

$w_t=12.8J$

Therefore

$Total energy\ E_t=Initial\ kinetic energy\ K.E*Work done\ by\ tunnel\ W_t$

$E_t=K.E+E_t\\E_t=768J+12.8J$

$E_t=780.8J$

Generally the energy lost while climbing is mathematically given as

$E_c=mgh$

$E_c=(6)(9.8)(2.9)$

$E_c=170.52J$

Generally the energy lost to friction is mathematically given as

$E_f=\alpha *m*g*cos\textdegree*d_c$

$E_f=0.21*6*9.8*cos16*1$

$E_f=11.86965942 \approx 12J$

Generally the energy left in the form of mass $Em$ is mathematically given as

$E_m=E_t+E_c+E_f$

$E_m=(768J)-(170.52)-(12)$

$E_m=585.48J$

Since

$E_m=\alpha_2*g*m*d$

Therefore

It slide along the second frictional region

$D=\frac{585.46}{0.1*9.81*6}$

$D=99.4665307m \approx 99.5m$

6 0

3 years ago

Near Earth, the density of protons in the solar wind (a stream of particles from the Sun) is 12.5 cm-3, and their speed is 564 k

morpeh [17]

Answer:

A) 11.28 x 10^(7) A.m²

B) 2.258 x 10^(17)A

Explanation:

A) The current density is given by the formula ;

J = nqv

Where n is the density of protons in the solar wind which is 12.5 cm³ or 12.5 x 10^(-6) m³

q is the proton charge which is 1.6 x 10^(-19) C

v is velocity which is 564km or 564000m

Thus, J = 12.5 x 10^(-6) x 1.6 x 10^(-19) x 564000 = 11.28 x 10^(7) A.m²

B) the formula for the total current the earth received is given as;

I = JA

The effective area is the cross section of the earth and thus,

Area = πr² where r is the radius of the earth given as: 6.371 x 10^(6)

A = π(6.371 x 10^(6)) ²

So I = 11.28 x 10^(7) x π(6.371 x 10^(6))² = 2.258 x 10^(17)A

7 0

3 years ago

Physics!!! Please help!!!!!!!

Marianna [84]

Answer:

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2 years ago