Answer: 30 metres
Explanation:
Initial velocity of object = 120m/s
Time taken = 4.0s
Distance covered by object = ?
Recall that distance = (Change in velocity / Time taken)
Distance = (120m/s)/4.0s
= (120m/s) / 4.0s
= 30m
Thus, the object will be 30 metres high
Electromagnetic waves are a type of
transverse wave. This wave does not
require media for travel. As the name
implies a wave, these waves indicate
electrical and magnetic properties. No
cost whatsoever happened to the wave. Electromagnetic waves work with the
laws of reflection and refraction. They
travel the straight line in a vacuum at a
speed of 3 x 108 ms-1. The intensity of
electromagnetic waves depends on the
strength of the electric field.
We have that for the Question "A 2kg book is held against a vertical wall. The <em>coefficient </em>of friction is 0.45. What is the minimum force that must be applied on the <em>book</em>, perpendicular to the wall, to prevent the book from slipping down the wal" it can be said that the minimum force that must be applied on the <em>book is</em>
From the question we are told
A 2kg book is held against a vertical wall. The <em>coefficient </em>of friction is 0.45. What is the minimum force that must be applied on the <em>book</em>, perpendicular to the wall, to prevent the book from slipping down the wal
Generally the equation for the Force is mathematically given as

F=44N
Therefore
the minimum force that must be applied on the <em>book is</em>
F=44N
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They circulate blood and oxygen throughout your body
Answer:
#_photon = 5 10²⁰ photons / s
Explanation:
For this exercise let's calculate the energy of a single quantum of energy, use Planck's law
E = h f
c= λ f
E = h c / λ
λ= 1000 nm (1 m / 109 nm) = 1000 10⁻⁹ m
Let's calculate
E₀ = 6.6310⁻³⁴ 3 10⁸/1000 10⁻⁹
E₀ = 19.89 10⁻²⁰ J
This is the energy emitted by a photon let's use a proportions rule to find the number emitted in P = 100 w
#_photon = P / E₀
#_photon = 100 / 19.89 10⁻²⁰
#_photon = 5 10²⁰ photons / s