1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Irina18 [472]
4 years ago
11

if a sample of ideal gas takes up 5.00 L at 300 K and 1.5 atm, what volume will it Take up at 400 K and 1.5 atm?

Chemistry
1 answer:
zysi [14]4 years ago
6 0

Answer:

The volume will be 6, 67 L

Explanation:

We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T:

P1xV1/T1 = P2 x V2/T2

V2= ((P1xV1/T1)xT2)/P2

V2=((1,5 atm x5 L/300K)x400K)/1,5 atm

V2=6, 67 L

You might be interested in
The half-life period for a first order reaction is independent of
maria [59]
I believe the answer is concentration

Sorry if I’m wrong hope this helps
4 0
3 years ago
Read 2 more answers
A buffer consists of 0.120 M HNO2 and 0.150 M NaNO2 at 25°C. pka of HNO2 is 3.40. a. What is the pH of the buffer? b. What is th
Mashcka [7]

Explanation:

It is known that K_{a} of HNO_{2} = 4.5 \times 10^{-4}.

(a)  Relation between K_{a} and pK_{a} is as follows.

                       pK_{a} = -log (K_{a})

Putting the values into the above formula as follows.

                      pK_{a} = -log (K_{a})

                                    = -log(4.5 \times 10^{-4})

                                     = 3.347

Also, relation between pH and  pK_{a} is as follows.

              pH = pK_{a} + log\frac{[conjugate base]}{[acid]}

                     = 3.347+ log \frac{0.15}{0.12}

                    = 3.44

Therefore, pH of the buffer is 3.44.

(b)   No. of moles of HCl added = Molarity \times volume

                                            = 11.6 M \times 0.001 L

                                             = 0.0116 mol

In the given reaction, NO^{-}_{2} will react with H^{+} to form HNO_{2}

Hence, before the reaction:

No. of moles of NO^{-}_{2} = 0.15 M \times 1.0 L

                                           = 0.15 mol

And, no. of moles of HNO_{2} = 0.12 M \times 1.0 L

                                               = 0.12 mol

On the other hand, after the reaction :  

No. of moles of NO^{-}_{2} = moles present initially - moles added

                                          = (0.15 - 0.0116) mol

                                          = 0.1384 mol

Moles of HNO_{2} = moles present initially + moles added

                               = (0.12 + 0.0116) mol

                                = 0.1316 mol

As, K_{a} = 4.5 \times 10^{-4}

           pK_{a} = -log (K_{a})

                         = -log(4.5 \times 10^{-4})

                         = 3.347

Since, volume is both in numerator and denominator, we can use mol instead of concentration.

As, pH = pK_{a} + log \frac{[conjugate base]}{[acid]}

            = 3.347+ log {0.1384/0.1316}

            = 3.369

            = 3.37 (approx)

Thus, we can conclude that pH after the addition of 1.00 mL of 11.6 M HCl to 1.00 L of the buffer solution is 3.37.

6 0
4 years ago
When Truman walks across the tile floor in his kitchen, the sound of his shoes is loud and sharp. Which of the following best de
Alexxx [7]

Answer:

Soft and quiet

Explanation:

6 0
3 years ago
!: (a) 20 cm: 80
RoseWind [281]

Answer:

THE LENGTH OF THE AIR COLUMN IS 9.5 CM

Explanation:

Taking the atmospheric pressure to be 760 mmHg;

When the capillary tube is held horizontally, the pressure of the tube is 760 mmHg

when the capillary tube is held vertically, the pressure increases by 4 cm = 40 mm

The new pressure of the tube is hence, 760 + 40 mmHg = 800 mmHg

Using the pressure forlmula;

P1 V1 = P2 V2

P1 A1 L1 = P2 A2 L2

where A1 and A2 is the area of the capillary tube and it is equal, it cancels out.

P1 l1 = P2 l2

l2 = P1 l1 / P2

l2 = 760 * 10 / 800

l2 = 9.5 cm

The length of the air in the tube is 9.5 cm.

5 0
3 years ago
A. What was the pH change when HCI was added to tap water?
Oxana [17]

Answer:

See below.

Explanation:

a. The pH would decrease.

b. An acid.

c. The pH would increase.

d. A base.  More accurately an alkali ( which is a soluble base).

5 0
3 years ago
Read 2 more answers
Other questions:
  • What are two elements that form a large number of bonds and that both have similar properties to carbon?
    5·1 answer
  • In a nuclear fusion reaction, what state is matter in?
    6·1 answer
  • What is the cause of rising surface temperatures of the Pacific Ocean, drought in the Western United States, flooding on the pac
    11·1 answer
  • What's an atom ?<br> Science
    5·2 answers
  • Determine the number of molecules in a 100. gram sample of CCl4
    13·1 answer
  • Which best explains why ionization energy tends to decrease from the top to the bottom of a group?
    7·2 answers
  • Which set of changes does not involve breaking or forming chemilcal bonds
    14·1 answer
  • A scientist discovers a deep bowl-like divot under the ocean off the coast of eastern Mexico that is many kilometers across. The
    13·2 answers
  • Consider the reaction: I2(g)+Cl2(g)⇌2ICl(g) Kp= 81.9 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under each condition: -
    11·2 answers
  • The density of butter is 0.86 g/cm3. what is the mass of 240 cm3 of butter?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!