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gtnhenbr [62]
3 years ago
11

A. What was the pH change when HCI was added to tap water?

Chemistry
2 answers:
GuDViN [60]3 years ago
7 0

<u>Answer:</u>

A)

<u>Solution:</u>

Adding a strong acid such as HCl to water results in the release of H+ ions.  

Arrhenius Theory: An acid is a substance which produces one or more hydrogen ions, (H+) in aqueous solution.

<u>Examples:</u>

HCl(aq)>(aq)H^+Cl^-(aq)

(H+) from the acid binds to neutral water molecules to form H_3O^+ raising the concentration of H+.  

The resulting large concentration of (H+) makes the solution more acidic and leads to a dramatic drop in the pH.

B)

<u>Solution :</u>

An acid is a substance which produces one or more hydrogen ions, (H+) in aqueous solution.

Examples:

HCl(aq)>(aq)H^+Cl^-(aq)

So, HCl is an acid.

C)

<u>Solution : </u>

A Base is a substance which produces one or more hydroxyl ion or hydroxide ion (OH-) in aqueous solution.

Examples :

KOH(s)> K^+(aq) +OH^-(aq)\\\\Ca(OH)_2(s)>Ca^{2+}(aq)  +2OH^- (aq)\\\\Al(OH)_3(s)> Al^{3+}(aq)+ 3OH^- (aq)

Please note: (aq) stands for aqueous which means in the presence of water that is, water acts as a solvent

The release of OH- ions makes the solution more basic and this leads to an increase in pH of the solution  

D)

<u>Solution:</u>

A Base is a substance which produces one or more hydroxyl ion or hydroxide ion (OH-) in aqueous solution.

Examples

KOH(s)> K^+(aq) +OH^-(aq)\\\\Ca(OH)_2(s)>Ca^{2+}(aq)  +2OH^- (aq)\\\\Al(OH)_3(s)> Al^{3+}(aq)+ 3OH^- (aq)

Please note: (aq) stands for aqueous which means in the presence of water that is, water acts as a solvent

So, NaOH is a Base.

Oxana [17]3 years ago
5 0

Answer:

See below.

Explanation:

a. The pH would decrease.

b. An acid.

c. The pH would increase.

d. A base.  More accurately an alkali ( which is a soluble base).

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Vikentia [17]

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<h3>Further explanation  </h3>

Density is a quantity derived from the mass and volume  

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\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}

ρ = density , g/cm³ or kg/m³  

m = mass  , g or kg

v = volume  , cm³ or m³  

A density of Lead : ρ = 11.4 g/cm³

the density in kg/m³ :

\tt 11.4~\dfrac{g}{cm^3}\times \dfrac{kg}{10^3~g}\times \dfrac{cm^3}{10^{-6}~m^3}=\boxed{\bold{1.14\times 10^4~\dfrac{kg}{m^3}}}

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