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geniusboy [140]
2 years ago
6

A ball rolls off a table with a horizontal velocity of 3 m/s. If it takes 0.3 seconds for the ball to reach the floor, how high

above the floor
is the tabletop? Consider the value of g approximately as 10 m/s2
Physics
1 answer:
LekaFEV [45]2 years ago
6 0

The height of the table above the ground is 0.45 m.

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

  • Horizontal velocity (u) = 3 m/s
  • Time (t) = 0.3 s
  • Acceleration due to gravity (g) = 10 m/s²
  • Height (h) =?

<h3>How to determine the height </h3>

The height of the table can be obtained by using the following formula:

h = ½gt²

h = ½ × 10 × 0.3²

h = 5 × 0.09

h = 0.45 m

Thus, the height of the table is 0.45 m

Learn more about motion under gravity:

brainly.com/question/26275209

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Whiat is quantum numbers describes the size and energy of an orbital?
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Answer:

The answer is the principal Quantum number (n)

Explanation:

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In the picture below, the candle is heating the water in the tank. Which picture shows how the water will move as it gets hot?
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The first picture, at the top, does.

5 0
2 years ago
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Explain why the extrapolated temperature is used to determine the maximun temperature of the mixture rather than the highest rec
Oksi-84 [34.3K]
The extrapolated temperature is used to define the maximum temperature of the mixture relatively than the highest recorded temperature in which the conclusion will effect in a higher specific heat value. Heat is bound to escape from whatever apparatus is using, therefore it is needed to account for the loss of the heat that does not go into increasing the temperature of the mixture. 
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3 years ago
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A tall, cylindrical chimney falls over when its base is ruptured. Treat the chimney as a thin rod of length 53.2 m. At the insta
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From an energy balance, we can use this formula to solve for the angular speed of the chimney

ω^2 = 3g / h sin θ

Substituting the given values:
ω^2 = 3 (9.81) / 53.2 sin 34.1
ω^2 = 0.987 /s

The formula for radial acceleration is:
a = rω^2

So,
a = 53.2 (0.987) = 52.494 /s^2

The linear velocity is:
v^2 = ar
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The tangential acceleration is:
a = r v^2
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If the tangential acceleration is equal to g:
g = r^2 3g / sin θ
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