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3 years ago

9

Write down about the water source selection criteria

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ololo11 [35]3 years ago

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Answer:

ssjsssmmmmdndkuctcxhhxhxjxk

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Which size of impurity atom, smaller impurity atom or larger impurity atom, when located near a dislocation, will nullify some o

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Smaller impurity atom will nullify some of the compressive strain of a dislocation in a crystal. Because, smaller impurity atoms located near a dislocation creates tensile strain on atoms around it thereby partially nullifying compressive strain at the dislocation.

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3 years ago

A) If a given directional antenna can receive 15 times the power of an isotropic antenna, what is

Sauron [17]

The gain of the directional antenna is calculated based on the comparison

with an hypothetical isotropic antenna.

a) The gain in dBi of the isotropic antenna is approximately <u>11.76 dBi</u>

b) The power received by the isotropic antenna is approximately <u>0.61 mW</u>

Reasons:

a) The number of times the power of the directional antenna is stronger than the isotropic antenna, G = 15 times

The gain in dBi is given as follows;

$\displaystyle G = \mathbf{10^{\dfrac{G(dBi)}{10} }}$

Which gives;

$\displaystyle 15 = 10^{\dfrac{G(dBi)}{10} }$

$\displaystyle \dfrac{G(dBi)}{10} = \frac{ln(15)}{ln(10)}$

$\displaystyle G(dBi)} = 10 \times \frac{ln(15)}{ln(10)} \approx 11.76$

The power gain of the isotropic antenna, G(dBi) ≈ <u>11.76 dBi</u>

b) When the gain of the directional antenna is 2.15 dBi and it received 1 mW of power, we have;

The number of times stronger the directional antenna is, is found as follows;

$\displaystyle G = 10^{\dfrac{2.15}{10} } \approx \mathbf{1.64}$

The 2.15 dBi directional antenna receives the signal approximately 1.64 times stronger than the isotropic antenna, therefore;

$\displaystyle The \ power \ received \ by \ the \ isotropic \ antenna = \frac{1 \, mW}{1.64} \approx \underline {0.61 \, mW}$

Learn more here:

brainly.com/question/17587029

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