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Evgen [1.6K]
3 years ago
10

If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C?

Physics
2 answers:
Lina20 [59]3 years ago
6 0

Answer : The correct option is, (A) 0.002010812m^3

Solution : Given,

Volume of mercury at 20^oC is 0.002m^3

As mercury is a liquid. So, we have to apply the volume of expansion of liquid.

Formula used for the volume expansion of liquid,

V_{T}=v_{1}[1+\gamma (T_{2}-T_{1})]

or,

V_{2}=V_{1}[1+\gamma (T_{2}-T_{1})]

where,

V_{T} = volume of liquid at temperature T^oC

V_{1} = volume of liquid at temperature 20^oC

V_{2} = volume of liquid at temperature 50^oC

\gamma = volume expansion coefficient of mercury at 20^oC is 0.00018 per centigrade

Now put all the given values in the above formula, we get

V_{2}=0.002[1+0.00018(50-20)]=0.0020108m^3

Therefore, the volume of mercury at 50^oC is, 0.0020108m^3

Natalka [10]3 years ago
5 0
By using the combined gas law which says that P1V1/T1 = P2V2/T2, assuming constant pressure, the volume at the required temperature can be obtained.((0.002 m3)(50+273.15))/(20+273.15) = volume 2 at 50 degrees C.
This gives the answer 0.0022048 m3
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Adding component wise, we have;

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