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Evgen [1.6K]
3 years ago
10

If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C?

Physics
2 answers:
Lina20 [59]3 years ago
6 0

Answer : The correct option is, (A) 0.002010812m^3

Solution : Given,

Volume of mercury at 20^oC is 0.002m^3

As mercury is a liquid. So, we have to apply the volume of expansion of liquid.

Formula used for the volume expansion of liquid,

V_{T}=v_{1}[1+\gamma (T_{2}-T_{1})]

or,

V_{2}=V_{1}[1+\gamma (T_{2}-T_{1})]

where,

V_{T} = volume of liquid at temperature T^oC

V_{1} = volume of liquid at temperature 20^oC

V_{2} = volume of liquid at temperature 50^oC

\gamma = volume expansion coefficient of mercury at 20^oC is 0.00018 per centigrade

Now put all the given values in the above formula, we get

V_{2}=0.002[1+0.00018(50-20)]=0.0020108m^3

Therefore, the volume of mercury at 50^oC is, 0.0020108m^3

Natalka [10]3 years ago
5 0
By using the combined gas law which says that P1V1/T1 = P2V2/T2, assuming constant pressure, the volume at the required temperature can be obtained.((0.002 m3)(50+273.15))/(20+273.15) = volume 2 at 50 degrees C.
This gives the answer 0.0022048 m3
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Answer:

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Explanation:

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Re-arranging the formula, we find an expression for v:

v=\sqrt{\frac{GM}{r}}

We see that:

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3 years ago
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Which is a complete sentence?
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Write about the similarities and differences between kinetic and potential energy. Include specific, real world example in your
lord [1]

Answer:

Energy is transformed from potential to kinetic and vice versa

Explanation:

The energy is transformed from mechanical to kinetic energy when the object changes its position with respect to a reference point, where it loses height but increases its speed. When the object is at maximum height with respect to a reference point, it will have its maximum potential energy value. When the object passes through the reference point it will have potential energy equal to zero, but this energy will become kinetic energy.

The most characteristic and real example is that of a pendulum at one end, as can be seen in the attached image.

When the pendulum is located at the top end, as shown in Figure 1, at that point the maximum potential energy will be held. Then the pendulum is released and when it passes through the reference point and its height is zero, with respect to that point, all potential energy will have become kinetic energy in the same way at this point the maximum speed of the pendulum will be set.

8 0
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A cylinder with rotational inertia I1 = 3.0 kg · m2 rotates clockwise about a vertical axis through its center with angular spee
erastova [34]

Answer:

ω = 1.83 rad/s clockwise

Explanation:

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ω1 = -5.4rad/s (clockwise being negative)

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By conservation of the momentum:

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Solving for ω:

\omega = \frac{I1 * \omega1 + I2*\omega2}{I1+I2}=-1.83rad/s

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8 0
3 years ago
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