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kherson [118]
3 years ago
6

How do quantum numbers relate to electrons? please explain?

Physics
1 answer:
alukav5142 [94]3 years ago
7 0
Quantum numbers<span> allow us to both simplify and dig deeper into electron configurations. Electron configurations allow us to identify energy level, subshell, and the number of electrons in those locations. If you choose to go a bit further, you can also add in x,y, or z subscripts to describe the exact orbital of those subshells (for example </span><span>2<span>px</span></span>). Simply put, electron configurations are more focused on location of electrons then anything else. 
<span>
Quantum numbers allow us to dig deeper into the electron configurations by allowing us to focus on electrons' quantum nature. This includes such properties as principle energy (size) (n), magnitude of angular momentum (shape) (l), orientation in space (m), and the spinning nature of the electron. In terms of connecting quantum numbers back to electron configurations, n is related to the energy level, l is related to the subshell, m is related to the orbital, and s is due to Pauli Exclusion Principle.</span>
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If your body is dehydrated, the control center in the brain will stimulate the release of a hormone which causes the reabsorptio
Yanka [14]

Answer:

It is an example of negative feedback mechanism

Explanation:

Negative feedback mechanism is the process by which the output of a system, process or mechanism is fed back into the input in order to reduce the error in the system.

In the system described in this question, the reabsorption of water is the output, a feedback signal is sent to the control center, which is the input in order to control the release of the hormone responsible for reabsorption of water into the blood.

7 0
3 years ago
A toy car has a kinetic energy of 8 J. What is its kinetic energy after a frictional force of 0.5 N has acted on it for 6 m?
Nezavi [6.7K]

Answer:

Final kinetic energy, KE_f=5\ J  

Explanation:

It is given that,

Kinetic energy of toy car, KE_i = 8\ J

Frictional force, F = 0.5 N

Distance, d = 6 m

We need to find the kinetic energy after this frictional force has acted on it. We know that frictional force is an opposing force. The work done by the toy car is given by :

W=F\times d

W=-0.5\ N\times 6\ m

W = -3 J

We know that the work done is equal to the change in kinetic energy. Let KE_f is the final kinetic energy.

W=KE_f-KE_i

-3=KE_f-8

KE_f=5\ J

So, the final kinetic energy is the toy car is 5 J. Hence, this is the required solution.

7 0
3 years ago
When a runner increases her speed from 75 m/s to 115 m/s in 25 s,her acceleration is _____
Angelina_Jolie [31]
The acceleration would actually be 1.6 m/s^2. Acceleration= final velocity-initial velocity/time taken. When you do that formula it comes out to equal that.
8 0
3 years ago
What are some ways that humans depend on the ocean?
yulyashka [42]

Answer:

A lot of the earth oxygen comes from the ocean around 50%-80%

Explanation:

5 0
3 years ago
Read 2 more answers
A light bulb is rated at 25 W when operated at 120 V. How much charge enters (and leaves) the light bulb in 1. 0 min?
aleksklad [387]

The amount of charge enters (and leaves) is 12 Coulomb.

<h3 /><h3>How can we find the value of the amount of charge enters (and leaves)?</h3>

Here we are using the formula,

I=\frac{P}{V} and Q= I \times t

We are given,

P = Power of the light bulb = 25 Watt.

V = The amount of voltage where the light bulb operated = 120 Volt.

t= The time when charge enters (and leaves) the light bulb = 1.0 min = (1 \times 60) second = 60 S

We have to find,

I= The amount of current flows in the light bulb.

Q= The amount of charge enters (and leaves) the light bulb.

Now we substitute the values of known parameters in the first equation, we find that,

I=\frac{P}{V}=\frac{25}{120}

Or, I= 0.20 A

The amount of current flows in the light bulb is 0.20 Ampere.

Now, we put the value of I in the second equation,

Q= I \times t= 0.20 \times 60

Or, Q=12 C

So, from the above calculations we can see that the amount of charge enters (and leaves) the light bulb is 12 Coulomb.

Learn more about the light bulb:

brainly.com/question/8979272

#SPJ4

3 0
2 years ago
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