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kherson [118]
3 years ago
6

How do quantum numbers relate to electrons? please explain?

Physics
1 answer:
alukav5142 [94]3 years ago
7 0
Quantum numbers<span> allow us to both simplify and dig deeper into electron configurations. Electron configurations allow us to identify energy level, subshell, and the number of electrons in those locations. If you choose to go a bit further, you can also add in x,y, or z subscripts to describe the exact orbital of those subshells (for example </span><span>2<span>px</span></span>). Simply put, electron configurations are more focused on location of electrons then anything else. 
<span>
Quantum numbers allow us to dig deeper into the electron configurations by allowing us to focus on electrons' quantum nature. This includes such properties as principle energy (size) (n), magnitude of angular momentum (shape) (l), orientation in space (m), and the spinning nature of the electron. In terms of connecting quantum numbers back to electron configurations, n is related to the energy level, l is related to the subshell, m is related to the orbital, and s is due to Pauli Exclusion Principle.</span>
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Density of solids What is your hypothesis (or hypotheses) for this experiment?.
valentina_108 [34]

I formulate a hypothesis based on their observations about what occurs when both the rock and the wood are submerged in water.

<h3 /><h3>What is density?</h3>

Density is defined as the mass per unit volume. It is an important parameter in order to understand the fluid and its properties. Its unit is kg/m³.

The mass and density relation is given as

mass = density × volume

I study if the volume or density of items determines whether solid objects float or sink in water in this scientific inquiry I did the experiment of density, mass, and volume using a rock and a standard-shaped piece of wood.

It is critical that the chosen piece of wood is larger than the rock and that the rock be tiny enough to fit inside the measuring cylinder. I see both the rock and a chunk of wood.

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brainly.com/question/952755

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2 years ago
HELP!!
QveST [7]

Answer:

Total displacement 155 m

Explanation:

From the question, the formula to apply will be that of cosine rule where:

c=\sqrt{a^2+b^2-2ab*cosC}

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a= 43 m , b=130m and c =? , <C=28° + 90° =118°

Substituting values in the equation as;

c=\sqrt{43^2+130^2-2*43*130*cos118}

c=\sqrt{1849+16900-11180*-0.46947} \\\\c=\sqrt{1849+16900+5249} \\\\c=\sqrt{23998} \\\\\\c=155m

6 0
3 years ago
What is the relation between the wavelength, λ, and the momentum, p, of a particle? Roughly what kinetic energy should an electr
prisoha [69]

Answer:

λ = h/p

<u>E=2.41*10^{-17}Joules</u>

This energy is equivalent to E=150.44eV

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<u>de Broglie Equation:</u>

λ = h/p

h=6.63×10-34 m2 kg / s        Planck's constant

so: p=h/λ

On the other hand, an atomic distance, an angstrom, is equal:10^{-10}m, λ should be similar to this distance.

<u>Kinetics Energy of a electron, m=9.11×10−31 kg</u>

<u>E=\frac{p^{2}}{2m_e}=\frac{h^{2}}{2\lambda^{2}m_e} =\frac{(6.63*10^{-34})^{2}}{2*(10^{-10})^{2}*9.11*10^{-31}}=2.41*10^{-17}Joules</u>

<u>Number of volts needed to accelerate that electron from rest to this energy:</u>

E=Vq_{e}

V=E/q_{e}=2.41*10^{-17}/(1.602*10^{-19})=150.44Volts

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This high-voltage device is called: particles accelerator

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