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Sunny_sXe [5.5K]
3 years ago
12

Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:

Chemistry
1 answer:
Leya [2.2K]3 years ago
8 0
<span>1) Use the balanced chemical equation to find the molar ratios (proportions) of each product and reactant.

3N2H4(l)→4NH3(g)+N2(g)

=> molar ratios: 3 mol N2H4 : 4 mol NH3

2) Use the product to reactant molar ratio, and the quantity of reactant to determine the yield:

2.0 mol N2H4 * [4mol NH3] / [3mol N2H4] = 2*4/3 mol NH3 = 2.7 mol NH3

Answer: 2.7 mol
 
</span>
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Answer:

3Na2SO4

Explanation:

3Na2SO4

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# of atoms: Na = 6 atoms, S= 3, O= 12

Total # of atoms: 21

The #3 is a Coefficient.

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Dominik [7]
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The pH of a solution is measured eight times by one operator using the same instrument. She obtains the following data: 7.15, 7.
sergiy2304 [10]

Answer:

7.186

Explanation:

The mean is the average of some given data from a sample point.

To calculate the mean, we use the formula below:

             Mean = ∑fx/∑f

Where f = frequency

           x = sample data

   

From the given pH of the solutions, we can form a table:

      x                                     f                                          fx

    7.15                                  1                                         7.15

    7.16                                  1                                         7.16

    7.18                                  1                                         7.18

    7.19                                  1                                         7.19

    7.20                                 3                                        21.6

    7.21                                  1                                         7.21

Now ∑fx = 7.15 +7.16 +7.18 + 7.19 + 7.20 + 7.21 = 57.49

         ∑f = 1 + 1 + 1 + 1 + 3 + 1 = 8

The mean = \frac{57.49}{8} = 7.18625 = 7.186

3 0
2 years ago
What is the specific heat of a substance if a mass of 10.0 kg increases in temperature from 10.0°C to 70.0°C when 2,520 J of hea
Ksju [112]

Answer:

A. 0.00420 J/(gi°C)

Explanation:

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