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Tasya [4]
3 years ago
10

Chromium metal is plated onto a car bumper at a current of 10.0 amperes for 100 seconds. The plating bath contains chromium in t

he form of CrO42− ions. How many grams of Cr are deposited in this process? (The atomic weight of Cr is 51.996 amu.)
Chemistry
1 answer:
Phoenix [80]3 years ago
6 0

Answer:

0.54g of Cr

Explanation:

Current (I) = 10A

Time (t) = 100s

Molecular mass of Cr = 51.996 amu

Faraday's first law of electrolysis states that

The mass of the substance (m) of a given substance deposited at an electrode is directly proportional to the quantity of electricity or charge (Q) passed

m = nQ

M = mass of the substance

n = electrochemical constant

Q = charge passed through it

Q = IT

Q = (10 * 100) = 1000C

1 moles = molarmass = Faraday's constant (96500C)

Molar mass = Faraday's constant (96500C)

51.996 g = 96500C

How many grams will be liberated with 1000C

51.996g = 96500C

Xg = 1000C

X = (1000 * 51.996) / 96500

X = 51996 / 96500

X = 0.5388g = 0.54 g of Cr will be deposited

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Answer:

\% diss = 50\%

Explanation:

Hello there!

In this case, when considering weak acids which have an associated percent dissociation, we first need to set up the ionization reaction and the equilibrium expression:

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Now, by introducing x as the reaction extent which also represents the concentration of both H+ and A-, we have:

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So that we can calculate the initial concentration of the acid:

\frac{(1.82x10^{-5})^2}{[HA]_0-1.82x10^{-5}} =1.82x10^{-5}\\\\\frac{1.82x10^{-5}}{[HA]_0-1.82x10^{-5}} =1\\\\

[HA]_0=3.64x10^{-5}M

Therefore, the percent dissociation turns out to be:

\% diss=\frac{x}{[HA]_0}*100\% \\\\\% diss=\frac{1.82x10^{-5}M}{3.64x10^{-5}M}*100\% \\\\\% diss = 50\%

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Place the following covalent bonds in order from least to most polar: a. H-Cl b. H-Br c. H-S d. H-C
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                                     C-H < S-H < H-Br < H-Cl


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