4 years ago

Question 8 what is The formula for atomic charge

Chemistry

1 answer:

Black_prince [1.1K]4 years ago

7 0

Answer:

Hope this may help you

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**Plz help with this asap who ever replies first with the right answer will get brainlists

Vesna [10]

Answer:first D. 88L

Second A 2*10^24

Explanation:

At stp 1 mole = 22.4L

mw Cl2= 70.9

280 g =280/70.9 moles, about 4

4*22.4 = about 88

aw Sr 87.6 —> 6.02214076*10^23 atoms = 1 mole

5 0

3 years ago

Which of the following are products of the reaction listed? Zn + 2HCI

Alexus [3.1K]

Answer:

uh A.)? [ZnCI2+H2]? /////////

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3 years ago

Curium – 245 is an alpha emitter. Write the equation for the nuclear reaction and identify the product nucleus.

BabaBlast [244]

Answer:

Please find the complete solution in the attached file.

Explanation:

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3 years ago

If the concentration of the stock (provided) Cu(NH3)42 was 0.041 M, what concentration will the Cu2 be in beaker?

kodGreya [7K]

Answer:

$[Cu^{2+}]=0.041 M$

Explanation:

Hello!

In this case, since the molarity of a solution is defined in terms of the moles of the solute and the volume of solution, given that the concentration of Cu(NH₃)₄²⁺ is 0.041 M, and there is only one copper atom per Cu(NH₃)₄²⁺ ion, we can compute the concentration of Cu²⁺ as shown below:

$[Cu^{2+}]=0.041\frac{molCu(NH_3)_4^{2+}}{L}*\frac{1molCu^{2+}}{1molCu(NH_3)_4^{2+}} =0.041 \frac{molCu(NH_3)_4^{2+}}{L}$

$[Cu^{2+}]=0.041 M$

Best regards!

6 0

3 years ago

What is the ratio of Al 3+ ions to S 2- ions in a neutral compound?

iren2701 [21]

In a neutral ionic compound, you can determine its sub-scripts by simply flipping the ionic charges and dropping the signs: so AlS would be Al2S3

4 0

3 years ago

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