All categories

3 years ago

Question 8 what is The formula for atomic charge

Chemistry

1 answer:

Black_prince [1.1K]3 years ago

7 0

Answer:

Hope this may help you

You might be interested in

What is the mass of 925.4 L of hydrogen gas at STP?

Ahat [919]

Answer:

If this is an idea gas then 1mol takes up 22.4L.

So, knowing how many L you have you can figure out how many mole syou have by doing a simple equation:

$\frac{1mol}{y} =\frac{22.4L}{925.4L}$

Solve for y.

Then, since you know how many moles you have use the ptable https://ptable.com/#Properties to figure out the mass in grams.

NOTE: The ptable tells you that 1mol of H = 1g.....so this should be an easy calculation :) enjoy

8 0

2 years ago

What is a supercontinent? please help me!

oee [108]

Answer:

earth land assembling together to form single large landmass

7 0

2 years ago

7. Iron combines with 4.00 g of Copper (11) nitrate to form 6.01 g of Iron (I) nitrate and 0.400 g copper

olga55 [171]

Answer:

222325332

Explanation:

4 0

2 years ago

Read 2 more answers

Explain why the law of conservation of energy can mean that we do not have unlimited sources of energy.

oee [108]

The law of conservation of energy states that energy can neither be created nor destroyed - it can only be converted from one form to another. It basically means that energy can't just appear, but has to be converted from existing energy; for example, the chemical energy in petrol is turned into electrical energy to power a car.Remember the total energy of universe is constant,,and no more energy can be drawn from out if we collect all universe's energy at a single point(its the big bang energy splitted during

5 0

2 years ago

What is the volume of 40.0 grams of argon gas at STP ?

MrRa [10]

Answer:

24.9 L Ar

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Moles
STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Aqueous Solutions

States of Matter

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 40.0 g Ar

[Solve] L Ar

Step 2: Identify Conversions

[PT] Molar Mass of Ar - 39.95 g/mol

[STP] 22.4 L = 1 mol

Step 3: Convert

[DA] Set up: $\displaystyle 40.0 \ g \ Ar(\frac{1 \ mol \ Ar}{39.95 \ g \ Ar})(\frac{22.4 \ L \ Ar}{1 \ mol \ Ar})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 24.9235 \ L \ Ar$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

24.9235 L Ar ≈ 24.9 L Ar

5 0

2 years ago